Question

我有一个表C8，其中包含gquestions，id，answer列。我正在尝试使用此HTML表单和PHP查询更新表中的字符串：

HTML

date

PHP

<form action="/reply" method="post">
    <textarea name="answer"></textarea><br>
    <input type="submit" value="Reply">
</form>

好的，在表单中我输入textarea 测试并点击回复并在页面中获得此结果：

$p_answer = $_POST["answer"]; $time = time(); mysql_query("UPDATE gquestions SET answer='$p_answer' AND date='$time' WHERE id='1'"); echo "UPDATE gquestions SET answer='$p_answer' AND date='$time' WHERE id='1'";

但在表格中，我在UPDATE gquestions SET answer='Test' AND date='1490982467' id='1'列中获得 0 而不是测试。为什么我在专栏中得到0？

Answer 1

列类型不同，可能int将其更改为varchar或answer for answer列。

您的查询错误

"UPDATE gquestions SET answer='$p_answer' AND date='$time' WHERE id='1'"

应该不应该和

"UPDATE gquestions SET answer='$p_answer',date='$time' WHERE id='1'"

Answer 2

更改

UPDATE gquestions SET answer='$p_answer' AND date='$time' WHERE id='1'

要

UPDATE gquestions SET answer='$p_answer', date='$time' WHERE id='1'

Answer 3

更新您的代码

UPDATE gquestions SET answer='Test' AND date='1490982467' id='1'

到

UPDATE gquestions SET answer='Test' , date='1490982467' id='1'

这是常见的格式

  UPDATE table_name
  SET column1 = value1, column2 = value2, ...
  WHERE condition;

通过mysql_query错误的变量帖子

3 个答案: