我想根据打开窗体的用户选择照片。
如果我在where子句中加上一个数字,“where id = 36”,它只显示ID 34的照片(静态)。我怎样才能让它变得动态?每个用户都有自己的照片,因此应该加载。代码如下。
$("#grid").kendoGrid({
dataSource: {
type: "odata",
transport: {
read: "https://demos.telerik.com/kendo-ui/service/Northwind.svc/Orders"
},
schema: {
model: {
fields: {
OrderID: { type: "number" },
Freight: { type: "number" },
ShipName: { type: "string" },
OrderDate: { type: "date" },
ShipCity: { type: "string" }
}
}
},
pageSize: 20,
serverPaging: true,
serverFiltering: true,
serverSorting: true
},
height: 550,
filterable: true,
sortable: true,
pageable: true,
columns: [{
field:"OrderID",
filterable: false
},
"Freight",
{
field: "OrderDate",
title: "Order Date",
format: "{0:MM/dd/yyyy}"
}, {
field: "ShipName",
title: "Ship Name"
}, {
field: "ShipCity",
title: "Ship City"
}
]
});
答案 0 :(得分:1)
您应该使用Parameter对象来添加它,而不是动态创建SQL语句。它通常更安全,并且在性能方面没有真正的惩罚
var con = new SqlConnection();
var cmd = new SqlCommand("select profilepic from users where id=@id", con);
cmd.Parameters.AddWithValue("@id", 36);
var pic = cmd.ExecuteScalar();