Question

我有一个问题是根据父子评论显示子评论。我不知道它是否是一个树枝或查询问题或其他。

我有一个回复表，其中包含使用字段（com_id）链接到我的评论表中的评论的子评论。

如果reply_level等于1，则只有我的回复表的com_id字段也引用同一个表的reply_id字段（参见图像，红线对角线）。

如何根据reply_id父级（reply_id（4）？

进行查询以选择reply_level（1），reply_id（6）

我的枝条代码：

＆＃13;

<h3 class="titleComments">Comments</h3>
    {% for comment in comments %}
        <p> <strong>{{ comment.author }}</strong> {{ comment.content }}</p>
        <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel0" value="{{ comment.id }}"  > answer </button>
    <div id="reply">
        {% if replys is defined %}
            {% for reply in replys %}
                {% if reply.getComParent() == comment.id and reply.level == 0%}
                    <p> <strong>{{ reply.author }}</strong> {{ reply.content }}</p>
                    <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel1" value="{{ reply.id }}" data-level="{{ reply.level1 }}" > answer </button>
                {% endif %}
                <div id="underReply1">
                    {% if reply.getComParent() ==  reply.id  and reply.level ==1 %}
                        <p> <strong>{{ reply.author }}</strong> {{ reply.content }}</p>
                        <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel2" value="{{ reply.id }}" data-level="{{ reply.level2 }}" > answer </button>
                    {% endif %}
                </div>
            {% endfor %}
        {% endif %}
        </div>
    {% else %}
       no comment(s).
    {% endfor %}

＆＃13;

结果：

子子如何不出现。看来，如果我添加第四个主要评论。它从子评论到评论工作，但我不能根据父子评论调用子评论。

谢谢

Answer 1

递归是根据某事物的深度做任意数量的循环的神奇词。

在你的情况下，你可以尝试这样的事情：

<h3 class="titleComments">Comments</h3>

{# imports macros contained in this file inside "me" variable #}
{% import _self as me %}

{# makes the variable exists and loopable whatever the case #}
{% set replies = replies|default([]) %}

{% for comment in comments %}
    <p><strong>{{ comment.author }}</strong> {{ comment.content }}</p>
    <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel0" value="{{ comment.id }}"> answer</button>

    {# fixes the non-unique id issue in your current code #}
    <div id="reply-{{ comment.id }}">
         {% if replies|length %}
             {% for reply in replies %}
                 {% if reply.getComParent() == comment.id and reply.level == 0 %}
                     <p> <strong>{{ reply.author }}</strong> {{ reply.content }}</p>
                     <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel{{ level }}" value="{{ reply.id }}" data-level="{{ reply.level1 }}" > answer </button>

                     {# here begins the magic #}
                     {{ me.displayReplies(replies, reply, 1) }}

                 {% endif %}
             {% endfor %}
        {% else %}
            no comment(s).
        {% endif %}
     </div>
{% endfor %}

{# macros are similar to functions in php and can call themselves recursivly #}
{% macro displayReplies(replyParent, replies, level) %}

    {# reimports macros to make this macro able to call himself #}
    {% import _self as me %}

    {% for replyChild in replies %}

    <div id="underReply{{ replyParent.id }}">
        {% if replyChild.getComParent() == replyParent.id and replyChild.level == level %}
            <p> <strong>{{ replyChild.author }}</strong> {{ replyChild.content }}</p>
            <button type="button" class="btn-primary btn-xs buttonAnswer btnLevel2" value="{{ replyChild.id }}" data-level="{{ replyChild.level2 }}" > answer </button>

            {# and we get deeper if needed #}
            {{ me.displayReplies(replyChild, replies, level + 1) }}

        {% endif %}
    </div>
    {% endfor %}

{% endmacro %}

顺便说一下，更简单的方法应该是使用相同的表进行评论和回复：

考虑以下背景：

comments:
    -
        id: 1
        parent_id: null
        content: comment 1
    -
        id: 2
        parent_id: null
        content: comment 2
    -
        id: 3
        parent_id: null
        content: comment 3
    -
        id: 4
        parent_id: 1
        content: reply comment 1
    -
        id: 5
        parent_id: 2
        content: reply comment 2
    -
        id: 6
        parent_id: 3
        content: reply comment 3
    -
        id: 7
        parent_id: 3
        content: reply comment 3
    -
        id: 8
        parent_id: 4
        content: reply of reply comment 3
    -
        id: 9
        parent_id: 8
        content: reply of reply of reply comment 3

以下的枝条代码：

{% import _self as me %}

{% macro displayComment(comments, parentComment, deepness = 0) %}

  {% if parentComment.parent_id is null %}
  Comment #{{ parentComment.id }} (deepness = {{ deepness }}): {{ parentComment.content }}
  {% else %}
    {% for i in 0..deepness %}  {% endfor %}Reply #{{ parentComment.id }} of #{{ parentComment.parent_id }} (deepness = {{ deepness }}): {{ parentComment.content }}
  {% endif %}

  {% import _self as me %}
  {% for childComment in comments if childComment.parent_id == parentComment.id %}
  {{ me.displayComment(comments, childComment, deepness + 1) }}
  {% endfor %}

{% endmacro %}

{% for comment in comments if comment.parent_id is null %}
{{ me.displayComment(comments, comment) }}
{% endfor %}

你最终会得到：

Comment #1 (deepness = 0): comment 1

    Reply #4 of #1 (deepness = 1): reply comment 1

        Reply #8 of #4 (deepness = 2): reply of reply comment 3

            Reply #9 of #8 (deepness = 3): reply of reply of reply comment 3

Comment #2 (deepness = 0): comment 2

    Reply #5 of #2 (deepness = 1): reply comment 2

Comment #3 (deepness = 0): comment 3

    Reply #6 of #3 (deepness = 1): reply comment 3

    Reply #7 of #3 (deepness = 1): reply comment 3

See fiddle

Answer 2

你能试试这个逻辑吗？

<div id="underReply1">
   {% if reply.getComParent() == comment.id and reply.level == 1 %}
   ...

我认为这就是你所需要的。由于回复ID可能与com父匹配。我不确定它会解决问题，但是请尝试一下，看看这些是你期望的结果。

根据父子评论

2 个答案: