Question

我有一个活动打开另一个活动，在此我无法使代码运行以在Android Studio中打开外部URL。应用程序中断... 我使用了互联网许可。

代码：

public void onClick(View v){
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_VIEW);
    intent.addCategory(Intent.CATEGORY_BROWSABLE);
    intent.setData(Uri.parse("https://www.google.com.br"));
    startActivity(intent);
}

我是否需要创建另一个JavaClass来输入这些代码，还是可以在MainActivity java中使用它？

logcat的

Process: br.com.vinnydantas.curriculo, PID: 3355
java.lang.IllegalStateException: Could not find method Linkedin(View) in a parent or ancestor Context for android:onClick attribute defined on view class android.widget.ImageView with id 'imageLinkedin'
    at android.view.View$DeclaredOnClickListener.resolveMethod(View.java:4479)
    at android.view.View$DeclaredOnClickListener.onClick(View.java:4443)
    at android.view.View.performClick(View.java:5198)
    at android.view.View$PerformClick.run(View.java:21147)
    at android.os.Handler.handleCallback(Handler.java:739)
    at android.os.Handler.dispatchMessage(Handler.java:95)
    at android.os.Looper.loop(Looper.java:148)
    at android.app.ActivityThread.main(ActivityThread.java:5417)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

Answer 1

你可以像这样打电话

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<body ng-app="myApp">
  <div ng-controller="myCtrl">
    {{name}} 123 {{name2}}
  </div>
</body>

打开外部URL时活动崩溃

1 个答案: