Question

您好我试图提取这个（＆＃34; Polk County＆＃34;，＆＃34; short_name＆＃34; =＆gt;＆＃34; Polk County＆＃34; ）在这个哈希的第3排，但我似乎只能得到＃34;波尔克县＆＃34; 这是我目前的代码：

{% for county_hash in location.address_components %}
 {% for county in county_hash %}
  {{ county.long_name }}
 {% endfor %}
{% endfor %}

{
"0" => {
    "long_name" => "426", "short_name" => "426", "types" => ["street_number"]
}, "1" => {
    "long_name" => "Swanee Drive", "short_name" => "Swanee Dr", "types" => ["route"]
}, "2" => {
    "long_name" => "Livingston", "short_name" => "Livingston", "types" => ["locality", "political"]
}, "3" => {
    "long_name" => "Polk County", "short_name" => "Polk County", "types" => ["administrative_area_level_2", "political"]
}, "4" => {
    "long_name" => "Texas", "short_name" => "TX", "types" => ["administrative_area_level_1", "political"]
}, "5" => {
    "long_name" => "United States", "short_name" => "US", "types" => ["country", "political"]
}, "6" => {
    "long_name" => "77351", "short_name" => "77351", "types" => ["postal_code"]
}, "7" => {
    "long_name" => "8238", "short_name" => "8238", "types" => ["postal_code_suffix"]
}

}

Answer 1

虽然我不清楚你在这里要问的是什么，但是下面的代码

{% for county_hash in location.address_components %}
  {% for county in county_hash %}
    {{ county.long_name }}
  {% endfor %}
{% endfor %}

return将long_names的所有426 Swanee Drive Livingston Polk County Texas United States 77351 8238字符串，即Polk County，就像您在评论中提到的那样。

如果您只需where，则必须使用{% for county_hash in location.address_components %} {% for county in county_hash %} {{ county.long_name | where: "shortname", "Polk County" }} {% endfor %} {% endfor %}过滤器：

{{1}}

Answer 2

感谢您的帮助，这种方法对我有用。

{% for county_hash in location.address_components %}
  {% for county in county_hash %}
    {% if county.long_name contains 'County' %}
     {{ county.long_name }}
    {% endif %}
  {% endfor %}
{% endfor %}

breadcrumbs

Hash的迭代：JekyII

2 个答案: