Question

我希望你能再一次帮助我，我仍然是编程的老手，所以请耐心等待。我收到了这个错误：

Traceback (most recent call last):
  File "C:\Python27\cx_Freeze exe Creator\Postcodezoekernl.py", line 136, in <module>
    postcodeinvoer = int(postcodeinvoer)
TypeError: int() argument must be a string or a number, not 'NoneType'

该程序有效，但是当我编译它时，它会在你关闭程序时发出错误，说代码有问题。我已经尝试删除该行但该程序在没有它的情况下不会工作，因为它将直接进入ELSE语句。 Postcode1是某些数字之间的范围。用户必须填写一个号码。如果数字在该范围内，它将显示msgbox。

elif keuze in week2:

        postcodeinvoer = easygui.enterbox(msg="Voer een postcode in:", title="Postcodezoeker")
        postcodeinvoer = int(postcodeinvoer)

        if postcodeinvoer in postcode1:
            easygui.msgbox(msg="[Woensdag 3 mei, 10 mei, 17 mei, 24 mei] [Donderdag 4 mei, 11 mei, 18 mei]", title=postcodeinvoer)
        elif postcodeinvoer in postcode2:
            easygui.msgbox(msg="[Dinsdag 2 mei, 9 mei, 16 mei, 23 mei] [Donderdag 4 mei, 11 mei, 18 mei]", title=postcodeinvoer)
        elif postcodeinvoer in postcode3:
            easygui.msgbox(msg="[Dinsdag 2 mei, 9 mei, 16 mei, 23 mei] [Donderdag 4 mei, 11 mei, 18 mei]", title=postcodeinvoer)

顺便说一句，是否可以将python文件编译为单个.exe文件？希望你们能帮助我。提前谢谢！

问题解决了！

Answer 1

int(something)如果可以从它的参数中设置int，则会引发TypeError或ValueError，因此最简单的解决方案是捕获异常并重试。但由于我们希望允许用户取消操作，我们仍然会再次测试None并退出

cancel = False
basemsg = msg = "Voer een postcode in:"
while True:
    postcodeinvoer = easygui.enterbox(msg=msg, title="Postcodezoeker")
    if postcodeinvoer is None:
        # user canceled
        cancel = True
        break
    try:
        postcodeinvoer = int(postcodeinvoer)
    except (TypeError, ValueError) as e:
        msg = "invalid value ! " + basemsg
    else:
        # ok, let's get out
        break

if cancel:
     # exit the program or whatever...
     raise SysExit()

# ok, proceed with the user's value

现在你似乎犯了一个常见的新手错误，就是认为如果某些事情由数字组成，那么它就是一个数字，而事实并非如此。邮政编码或电话号码通常是字符串，而不是整数 - 问问自己将电话号码乘以2并将结果除以邮政编码会有什么意义;）

我不应该将postcodeinvoer转换为int。如果您所在的国家/地区的邮政编码仅由数字组成（在所有国家/地区都不是这种情况），那么您可以测试用户输入是由N位组成的字符串（ N的值取决于您所在的国家/地区：

    postcodeinvoer = easygui.enterbox(msg=msg, title="Postcodezoeker")
    if postcodeinvoer is None:
        # user canceled
        cancel = True
        break
    if (postcodeinvoer.isdigit() and len(postcodeinvoer) == N):
        # valid code
        break
    else:
        # invalid code, ask again
        msg = "invalid value ! " + basemsg

但即便如此，它可能还不够好......

Answer 2

检查postcodeinvoer不是无。

if postcodeinvoer:
    postcodeinvoer = int(postcodeinvoer)

关闭时Python程序错误

2 个答案: