这是我的解决方案，希望它对您有用。任何有同样困惑这个问题的人！

Question

我做了一个get，它返回一个像这样的json对象：

        "data": [
[
"2016 Pass/Fail Rates by Test Centre",
"",
"",
"",
"",
"",
"",
"",
"",
""
],
[
"",
"Passes",
"",
"No ID",
"",
"Fails",
"",
"Fail Dangerous",
"",
"Total"
],
[
"Sometown",
"8,725",
"53.40%",
"140",
"0.90%",
"7,417",
"45.40%",
"48",
"0.30%",
"16,330"
],
[
"Some Other Town",
"12,778",
"44.80%",
"193",
"0.70%",
"15,422",
"54.10%",
"103",
"0.40%",
"28,496"
],
[... many more identically formatted arrays ...]

我想最终：

[{"Location":"Sometown", "Passes":8,725, "Pass%":53.40%, "No ID":140, "NoID%":0.90%, "Fails":7,417, "Fail%":45.40%, "Fail Dangerous":48, "FailDangerous%":0.30%, "Total":16,330}, {"Location":"Some Other Town", "Passes":8,725, etc etc...

所以我想忽略＆＃34;数据中的第一个数组＆＃34;数组，使用第二个数组的值作为键（并用更有用的东西替换空字符串），并将所有剩余数组中的值作为结果对象中的值。

所以这是多部分问题，尽管我怀疑是一个相当简单的问题。最简单的方法是什么 - 如果不同，在处理/页面加载方面最简单的方法是什么？

提前致谢，

Answer 1

这是我的解决方案，希望它对您有用。任何有同样困惑这个问题的人！

你应该构建一个有意义的对象！

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const meaningful_objs = {
    "Location": "",
    "Passes": "",
    "Passes%": "",
    "No ID": "",
    "No ID%": "", 
    "Fails": "",
    "Fails%": "",
    "Fail Dangerous": "",
    "Fail Dangerous%": "",
    "Total": ""
};

// or get it from you data[1], 
// but I think it has some errors of you got returned data!
// It should be have all keys!

// just make a assume, you get the right data[1]!

const data[1] = ["Location", "Passes", "Passes%", "No ID", "No ID%", "Fails", "Fails%", "Fail Dangerous", "Fail Dangerous%", "Total"]; 

let keys = data[1];

Answer 2

您可以将第二个数组作为所需对象的键，并仅在键之后迭代该部分。然后迭代键并为数组的值构建一个新对象。返回对象以便为新数组进行映射。

＆＃13;

var data = { data: [["2016 Pass/Fail Rates by Test Centre", "", "", "", "", "", "", "", "", ""], ["Location", "Passes", "Passes%", "No ID", "No ID%", "Fails", "Fails%", "Fail Dangerous", "Fail Dangerous%", "Total"], ["Sometown", "8,725", "53.40%", "140", "0.90%", "7,417", "45.40%", "48", "0.30%", "16,330"], ["Some Other Town", "12,778", "44.80%", "193", "0.70%", "15,422", "54.10%", "103", "0.40%", "28,496"]] },
    keys = data.data[1],
    result = data.data.slice(2).map(function (a) {
        var temp = {};
        keys.forEach(function (k, i) {
            temp[k] = a[i];
        })
        return temp;
    });
    
console.log(result);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 3

您可以在将索引和值添加到对象中时迭代数组...

您可以找到有关如何迭代对象和数组的示例here以及示例here

Generally, to add an item to object

var array = [{"Location":"Sometown"}, {"Location2":"Sometown2"},    {"Location3":"Sometown3"}],
object = {};
array.forEach(function(element, index) {
    object[index] = element;
});
console.log(object);

将数组值转换为对象键

3 个答案:

这是我的解决方案，希望它对您有用。任何有同样困惑这个问题的人！