Question

我正在尝试使用Symfony创建AJAX表单，但我的表单返回空对象。当我发送manualy写文本或数组时，一切正常。这个bug在哪里？我对表单或javascript代码做错了什么问题？

/**
* Renders the "new" form
* 
* @Route("/", name="demo_new")
* @Method("GET")
*/
public function newAction(Request $request) {
    $entity = new Demo();
    $form = $this->createForm(DemoType::class, $entity);

    return $this->render('default/new.html.twig', array(
            'entity' => $entity,
            'form' => $form->createView()
            )
    );
}

/**
*
* @Route("/", name="demo_create")
* @Method("POST")
*
*/
 public function createAction(Request $request) {
if (!$request->isXmlHttpRequest()) {
  return new JsonResponse(array('message' => 'You can access this only using Ajax!'), 400);
}

$entity = new Demo();
$form = $this->createForm(DemoType::class, $entity, array(
    'action' => $this->generateUrl('demo_create'),
    'method' => 'POST',
));

$form->handleRequest($request);

if ($form->isSubmitted() && $form->isValid()) {
  $data = $form->getData();
  return new JsonResponse(
          [
            'message' => 'Success!',
            'data' => $data 
          ], 200);
}

$response = new JsonResponse(
        array(
    'message' => 'Error',
    'form' => $this->renderView('default/new.html.twig', array(
        'entity' => $entity,
        'form' => $form->createView(),
    ))), 400);
return $response;
 }
}

和Javascript代码：

  function initAjaxForm()
    {
    $('body').on('submit', '.ajaxForm', function (e) {

    e.preventDefault();

    $.ajax({
        type: $(this).attr('method'),
        url: $(this).attr('action'),
        data: $(this).serialize()
    })
    .done(function (data) {
        if (typeof data.message !== 'undefined') {
            console.log(data.data);
            console.log(data.message);
        }
    })
    .fail(function (jqXHR, textStatus, errorThrown) {
        if (typeof jqXHR.responseJSON !== 'undefined') {
            if (jqXHR.responseJSON.hasOwnProperty('form')) {
                $('#form_body').html(jqXHR.responseJSON.form);
            }

            $('.form_error').html(jqXHR.responseJSON.message);

        } else {
            alert(errorThrown);
        }

    });
});
}

Answer 1

今天有同样的问题，版本2.8会留在这里，以防它最终痊愈别人我已将此添加到我的表单构建器

/**
 * {@inheritdoc}
 */
public function getBlockPrefix()
{
    return '';
}

Symfony表单AJAX返回空对象

1 个答案: