Question

首先，它检查请求表单是否在数据库中具有相同的用户名，然后检查数据库中保存的第一个名称是否与请求表单进行比较。但它没有进入数据库我可能在将字符串转换为数组或使用for循环来比较两个字符串时做错了但我无法发现错误你能帮助我吗？

if (User::where('username', $request->username)->exists()) {//check if request form has the same username in the database

    //first name that is saved in the database to be compared with the request form
    $fnameSavedInDatabase = DB::select('select first_name from users where username = ? and first_name != ?', [$request->username, $request->first_name]);

    //turn into array
    $fnameSavedInDatabaseArray = str_split($fnameSavedInDatabase);

    //request form value turn in to an array
    $fnameIncomingArray = str_split($request->first_name);

    //value that will be saved/updated in the database
    $fnameFinalIncomingString;

    for ($index = 0; $index < strlen($request->first_name); $index++) {
        if ($fnameIncomingArray[$index] == $fnameSavedInDatabaseArray[$index]) {
            $fnameFinalIncomingString = $fnameFinalIncomingString . $fnameIncomingArray[$index];
        }
    }

    $user = User::create($request->all());

    $user->update(['role_id' => $request->role]);
    $user->save();
    $user->update(['username' => $fnameFinalIncomingString]);
    $user->save();

    $roleName = $user->role()->name;

    return response()->json(['user' => $user, 'roleName' => $roleName, 'manager_exists' => '0']);
}

Answer 1

检查您的模型用户。它必须在

protected $fillable = ['username',....]

然后在你的dev envirenoment中使用修补程序调试更新用户名而没有乱七八糟。

in cmd

php artisan tinker

然后

$user = \App\User::find(1);
$user->update(['username' => 'mytestname']);

Laravel字符串未在数据库中输入/更新

1 个答案: