Question

我想创建一个程序，让您尝试三次查找任何给定的数字。它基本上是一个猜谜游戏。问题是，我必须在没有任何循环的情况下这样做。到目前为止，我只能从用户那里获得输入，阅读该输入并告诉他们他们是否赢了或“输了”游戏。程序只运行一次并停止（如预期的那样）。

我被告知可以在没有循环的情况下完成，尽管代码更多。你能告诉我这里我做错了什么，并给我一些关于我应该改变什么的指示？如果您需要澄清，请告诉我。感谢。

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {

        Scanner ran = new Scanner(System.in);
        System.out.println("Enter a number: ");
        int x = ran.nextInt();

        if (x < 3) {
            System.out.println("Too low. Try again.");

            System.out.println("Enter a number: ");
        } else if (x > 3) {
            System.out.println("Too high. Try again");

        } else if(x == 3) {
            System.out.println("You win. Nice job.");
        } else {
            System.out.println("You lose");
        }

        System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
    }
}

Answer 1

您可以使用递归来完成此操作。看这个程序。在评论中查找解释。

import java.util.Scanner;

public class HelloWorld {

    private static Scanner ran = new Scanner(System.in);

    //this is number of tries you want to give to user
    private static int counter = 5;

    //The actual number
    private static final int NUM = 3;

    public static boolean guessingMachine() {
        //counter indicates that number of attempts remaining
        if(counter == 0) {
            return false;
        }
        counter--;

        System.out.println("Enter a number: ");
        int x = ran.nextInt();

        if (x < NUM) {
            System.out.println("Too low. Try again.");
            //try again... call this method again
            return guessingMachine();
        } else if (x > NUM) {
            System.out.println("Too high. Try again");
            //try again... call this method again
            return guessingMachine();
        } else {
            //x == NUM success
            return true;
        }
    }


    public static void main(String[] args) {
        boolean result = guessingMachine();

        if(result) 
            System.out.println("You win. Nice job.");
        else 
            System.out.println("You lose");

        System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
    }
}

Answer 2

你可以接下来的条件：

get user input
if input is correct, congratulation user and exit
    else
        get user input //second attempt
        if input is correct, congratulation user and exit
...

你可以从那里继续。您提供的代码，您告诉用户它们是否太高或太低，必须包含在上述伪代码的每个分支中。

Answer 3

我认为本练习的主要目的是为了加强嵌套的if-else概念。

import java.util.Scanner;

公共类HelloWorld {

 public static void main(String []args){
    int num=3;
    int count=1;
    Scanner ran = new Scanner(System.in);
    System.out.println("Enter a number: ");
    int x = ran.nextInt();

    if(x>num || x<num)
    {
        System.out.println("incorrect guess");
        count++;
        System.out.println("Enter a number: ");
         x = ran.nextInt();
         if(x>num || x<num)
         {
              System.out.println("incorrect guess");
              count++;
                          System.out.println("Enter a number: ");
                           x = ran.nextInt();
                           if(x>num || x<num)
                           {
                               System.out.println("incorrect guess YOU LOSE");
                           }
                           else
                           {
                                               System.out.println("YOU WIN");
                           }
         }
         else
         {
               System.out.println("YOU WIN");
         }

    }

    if(x==num && count==1)
    {
        System.out.println("YOU WIN");
    }

    System.out.println("Number Guessing Game (c) 2017 Anna Gibson");
 }
}

猜一个数字

3 个答案: