我有一个字符串:
<robot generated="20170330 17:19:11.956" generator="Robot 3.0.2 (Python 2.7.13 on win32)">
我想获得“生成”的值,但是使用下面的代码,它不起作用
import re
doc=r'<robot generated="20170330 17:19:11.956" generator="Robot 3.0.2 (Python 2.7.13 on win32)">'
match = re.match(r'generated="(\d+ \d+:\d+:\d+.\d+)',doc)
匹配的值是none。有人可以帮忙吗?
答案 0 :(得分:1)
re.match
仅匹配字符串的开头。使用re.search
代替不仅在开头匹配,而且匹配任何地方。
>>> import re
>>> doc=r'<robot generated="20170330 17:19:11.956" generator="Robot 3.0.2 (Python 2.7.13 on win32)">'
>>> re.search(r'generated="(\d+ \d+:\d+:\d+\.\d+)',doc)
<_sre.SRE_Match object at 0x1010505d0>
>>> re.search(r'generated="(\d+ \d+:\d+:\d+\.\d+)',doc).group()
'generated="20170330 17:19:11.956'
>>> re.search(r'generated="(\d+ \d+:\d+:\d+\.\d+)',doc).group(1)
'20170330 17:19:11.956'
答案 1 :(得分:1)
在这种情况下,您不一定需要正则表达式。以下是将BeautifulSoup
XML/HTML parser与dateutil
datetime parser一起使用的另一种想法:
In [1]: from dateutil.parser import parse
In [2]: from bs4 import BeautifulSoup
In [3]: data = '<robot generated="20170330 17:19:11.956" generator="Robot 3.0.2 (Python 2.7.13 on win32)">'
In [4]: parse(BeautifulSoup(data, "html.parser").robot['generated'])
Out[4]: datetime.datetime(2017, 3, 30, 17, 19, 11, 956000)
我发现这种方法美观,简单,直接。