在ORACLE中添加新值后更新列

时间:2017-03-31 02:24:42

标签: sql oracle

我有一些麻烦创造一个触发器,它将获得一个人拥有的当前点,检查他将获得什么奖励,然后更新他的奖励头衔。所以这就是场景:

     PersonTable
    | Person (PK) | RewardTitle (FK) | Score|
    | A           | Beginner         | 0    |
    | B           | MidRange         | 17   |
    | C           | Professional     | 32   |

     RewardTable
    | RewardTitle (PK) | BottomScore | UpperScore| Reward        |
    | Beginner         | 0           | 9         | Free food     |
    | MidRange         | 10          | 19        | Free games    |
    | Professional     | 20          | 100       | Unlimited time|

情况是,我想更新人A,以便他得到11分,然后找出他的新点属于哪个RewardTitle,并相应地改变他的奖励标题,所以因为他有11分,他的奖励标题现在将是中等范围。

我试图创建一个触发器,试图找到他所属的RewardTitle,然后相应地更新这个值,但我一直收到错误说:

    Person is mutating, trigger/function may not see it

我明白了这个问题,但我想不出任何其他方法来实现这个结果。我尝试过使用

    pragma autonomous_transaction;

但它仍然无效,以下是我的尝试:

    UPDATE PersonTable
    SET Score = 11
    WHERE Person = 'A';

    DELIMITER //
    CREATE OR REPLACE TRIGGER person_upd_trigger
    AFTER UPDATE ON PersonTable
    FOR EACH ROW
    DECLARE
        temp_variable VARCHAR(120);
    BEGIN
        SELECT r.RewardTitle INTO temp_variable
        FROM PersonTable p, RewardTable r
        WHERE :NEW.Person = p.Person
        AND p.Score BETWEEN r.BottomScore AND r.UpperScore;

        UPDATE PersonTable
        SET RewardTitle = temp_variable
        WHERE :NEW.Person = Person;
   END;

我将非常感谢能得到的所有帮助,我对Oracle SQL很陌生。三江源

1 个答案:

答案 0 :(得分:2)

您无法在BEFORE TRIGGER中更新已经更新的同一个表(如果认为允许会导致无限循环)。相反,您需要将触发器重新编写为:

为了实现这一点,您应该将触发器定义更改为BEFORE

CREATE OR REPLACE TRIGGER person_upd_trigger
BEFORE UPDATE ON PersonTable -- declare it as BEFORE
FOR EACH ROW
DECLARE
    temp_variable VARCHAR(120);
BEGIN
    SELECT r.RewardTitle INTO temp_variable
    FROM RewardTable r
    WHERE :NEW.Score BETWEEN r.BottomScore AND r.UpperScore;

    -- here you are setting the new value, no need for an update.
    :NEW.RewardTitle := temp_variable;
END;