Question

删除重复项是没有问题的，我遇到了一个问题，我不仅要删除副本，还要删除在SELECT语句中引起重复的原始行。

ItemNUMBER  ID    from_DATE   to_DATE   fancy_code
1           100   3/28/2015   4/10/2015    Z5111
2           100   4/18/2015   4/21/2015    Z5112
3           100   5/2/2015    5/5/2015     Z5111
4           100   5/31/2015   6/2/2015     Z5111
5           100   7/31/2015   8/16/2015    A400       --remove
6           100   7/31/2015   8/16/2015    A400       --remove

上面是我的表， - 删除是最终目标。任何帮助将不胜感激！

Answer 1

强力方法是使用窗口函数：

with t as (
      <your query here>
     )
select t.*
from (select t.*,
             count(*) over (partition by ID, from_DATE, to_DATE, fancy_code) as cnt
      from t
     ) t
where cnt = 1;

更智能的方法是修复查询或导致重复的数据。当然，在某些情况下无法进行此类修复，因此您需要使用强力方法。

Answer 2

在列表中

SELECT MIN(ItemNUMBER), from_DATE, to_DATE, fancy_code
FROM yourTable
GROUP BY ID, from_DATE, to_DATE, fancy_code
HAVING COUNT(*) = 1

如果需要DELETE

DELETE FROM yourTable
WHERE ItemNUMBER  NOT IN (
    SELECT MIN(ItemNUMBER) as ItemNUMBER
    FROM yourTable
    GROUP BY ID, from_DATE, to_DATE, fancy_code
    HAVING COUNT(*) = 1
   )

Answer 3

您可以在这些行上使用连接选择它们。

SELECT ItemNUMBER, ID, from_DATE, to_DATE, fancy_code
FROM [Table] t join (
    SELECT ItemNUMBER, ID, from_DATE, to_DATE, count(1)
    FROM [Table] t
    GROUP BY ItemNUMBER, ID, from_DATE, to_DATE
    HAVING count(1) = 1
) u on (u.ItemNUMBER= t.ItemNUMBER and u.ID=t.ID 
    and u.from_DATE=t.from_DATE and u.to_DATE = t.to_DATE)

根据原始表中的密钥调整味道（ID将是候选者）。

Answer 4

通常会删除双重条目

第1步：获取重复的条目
步骤2：从重复条目中识别项目编号第3步：删除那些项目数

DELETE FROM table1
WHERE itemnumber IN (SELECT
    itemNumber
  FROM table1 z
  INNER JOIN (SELECT
    fancy_code,
    id,
    from_date,
    to_date
  FROM table1 x
  GROUP BY fancy_code,
           id,
           from_date,
           to_date
  HAVING COUNT(*) > 1) y
    ON y.fancy_code = z.fancy_code
    AND y.id = z.id
    AND y.from_date = z.from_date
    AND y.to_date = z.to_date)

Answer 5

如果您到达表格中的重复ItemNUMBER，则可以通过简单的WHERE子句删除所有这些内容。

为了做到这一点，您需要使用表格内部JOIN，然后使用GROUP - BY您可以访问的DELETE theTable WHERE ItemNUMBER IN ( SELECT t1.ItemNUMBER FROM theTable t1 JOIN theTable t2 ON t1.ID = t2.ID AND t1.from_DATE = t2.from_DATE AND t1.to_DATE = t2.to_DATE AND t1.fancy_code = t2.fancy_code GROUP BY t1.ItemNUMBER HAVING COUNT(t1.ItemNUMBER) > 1 )可重复列。目的。

因此查询可以类似于以下内容：

span {
  position: absolute;
  right: 150px;                  /* width of Right element */
  white-space: nowrap;           /* prevent wrapping */
  min-width: calc(100% - 350px); /* difference of Left and Right widths */
}

#leftside {
  z-index: 1;                   /* cover the middle element if needed */
}

Answer 6

使用CTE和count（*）最简单的方法。

WITH cte AS
(
  SELECT fkledgeraccid,  ROW_NUMBER() OVER (PARTITION BY ID,from_DATE,to_DATE,fancy_code) AS row
  FROM TABLE1
) 
Select * from cte where row=1

删除重复项以及原始行

6 个答案: