Question

我知道以前曾经问过，但我似乎无法找到答案。我只想知道如何访问service_name array

中console.log中的值

下面是数组，只是从数据中删除。

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]


console.log(JSON.stringify(a, 0, 4))

Answer 1

你可以像数组一样访问它，这就是你如何访问数组中第4项的service_name值

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]


console.log(JSON.stringify(a[3].service_name[0]))
console.log(JSON.stringify(a[3].service_name[1]))

Answer 2

只是做：

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]
a.forEach((e)=>console.log(e.service_name));

如果您需要结果数组：

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]
var res = a.map((e)=>e.service_name);
console.log(res);

Answer 3

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]

a.forEach(function(element) {
  console.log(element.service_name);
});

Answer 4

您可以创建一个函数来返回其ID与您要查找的ID匹配的元素的服务名称数组，如下所示：

＆＃13;

function getServiceNamesById (data, id) {
  for (var i = 0; i < data.length; i++) {
    if (data[i].ID === id) {
      return data[i].service_name;
    }
  }
  return [];
}

var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}];

var id = 226619;

console.log(getServiceNamesById(a, id));

＆＃13;

Answer 5

试试这个：

  var a = [{"ID":102254,"Name":"obj 1","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":226619,"Name":"DIDE","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":224522,"Name":"CAT","service_name":["Open  Ticket","Escalation Ticket"]},{"ID":122533,"Name":"Mirror","service_name":["Open  Ticket","Escalation Ticket"]}]

 a.forEach(function(item){ // item is an object
     item.service_name.forEach(function(service){ //item.service_name is  an array
     console.log(service);
     });
 });

祝你好运

如何访问嵌套对象数组Javascript

5 个答案: