Question

现在已经坚持了一段时间了。假设我有一个像这里的Client表：

Name   BirthDayNum   BirthMonthNum   BirthYearNum
--------------------------------------------------
John       23             12             1965
Jane        4              9             1975
Joe         6              3             1953

目前我正在使用以下语法计算年龄:(对不起，如果难以阅读）

DATEDIFF(year, CONVERT(datetime, CAST(client.BirthMonthNum AS varchar(2)) 
+ '-' + CAST(client.BirthDayNum AS varchar(2)) 
+ '-' + CAST(client.BirthYearNum AS varchar(4)), 101), GETDATE()) 
- (CASE WHEN dateadd(YY, DATEDIFF(year, CONVERT(datetime, CAST(client.BirthMonthNum AS varchar(2)) 
+ '-' + CAST(client.BirthDayNum AS varchar(2)) 
+ '-' + CAST(client.BirthYearNum AS varchar(4)), 101), GETDATE()), 
CONVERT(datetime, CAST(client.BirthMonthNum AS varchar(2)) 
+ '-' + CAST(client.BirthDayNum AS varchar(2)) 
+ '-' + CAST(client.BirthYearNum AS varchar(4)), 101)) > getdate() THEN 1 ELSE 0 END) AS 'Client Age'

这将给我多年的年龄。当然，如果我想要几个月，我只需将DATEDIFF(year更改为month。那么，我现在要做的就是这个。

继续计算年龄，但我不想返回几年或几个月，而是希望以年和月为单位返回年龄，而且还要在值内连续“y”和“m”。防爆。 Jane上面41码11米。

所以基本上我试图弄清楚如何在返回值中添加一个字符，以及计算年度计算之外的剩余月数。

非常感谢任何帮助！

Answer 1

厌倦了用日期计算将自己扭曲成结，我创建了一个表值函数来计算年，月，日，小时，分钟和秒的经过时间。

示例

Declare @YourTable table (Name varchar(50),BirthDayNum int, BirthMonthNum int, BirthYearNum int) Insert Into @YourTable values ('John', 23, 12, 1965), ('Jane', 4, 9, 1975), ('Joe', 6, 3, 1953) Select A.Name ,B.* ,Age = concat(C.Years,'y ',C.Months,'m') From @YourTable A Cross Apply (Select DOB = DateFromParts(A.BirthYearNum,A.BirthMonthNum,A.BirthDayNum)) B Cross Apply [dbo].[udf-Date-Elapsed](B.DOB,GetDate()) C

<强>返回

Name DOB Age John 1965-12-23 51y 3m Jane 1975-09-04 41y 6m Joe 1953-03-06 64y 0m

UDF - 可能看起来有点矫枉过正，但效果非常好

CREATE FUNCTION [dbo].[udf-Date-Elapsed] (@D1 DateTime,@D2 DateTime) Returns Table Return ( with cteBN(N) as (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)), cteRN(R) as (Select Row_Number() Over (Order By (Select NULL))-1 From cteBN a,cteBN b,cteBN c), cteYY(N,D) as (Select Max(R),Max(DateAdd(YY,R,@D1))From cteRN R Where DateAdd(YY,R,@D1)<=@D2), cteMM(N,D) as (Select Max(R),Max(DateAdd(MM,R,D)) From (Select Top 12 R From cteRN Order By 1) R, cteYY P Where DateAdd(MM,R,D)<=@D2), cteDD(N,D) as (Select Max(R),Max(DateAdd(DD,R,D)) From (Select Top 31 R From cteRN Order By 1) R, cteMM P Where DateAdd(DD,R,D)<=@D2), cteHH(N,D) as (Select Max(R),Max(DateAdd(HH,R,D)) From (Select Top 24 R From cteRN Order By 1) R, cteDD P Where DateAdd(HH,R,D)<=@D2), cteMI(N,D) as (Select Max(R),Max(DateAdd(MI,R,D)) From (Select Top 60 R From cteRN Order By 1) R, cteHH P Where DateAdd(MI,R,D)<=@D2), cteSS(N,D) as (Select Max(R),Max(DateAdd(SS,R,D)) From (Select Top 60 R From cteRN Order By 1) R, cteMI P Where DateAdd(SS,R,D)<=@D2) Select [Years] = cteYY.N ,[Months] = cteMM.N ,[Days] = cteDD.N ,[Hours] = cteHH.N ,[Minutes] = cteMI.N ,[Seconds] = cteSS.N From cteYY,cteMM,cteDD,cteHH,cteMI,cteSS ) --Max 1000 years --Select * from [dbo].[udf-Date-Elapsed] ('1991-09-12 21:00:00.000',GetDate())

只是为了说明

没有任何辅助字符串操作的TVF将返回

Select A.Name ,B.* From @YourTable A Cross Apply [dbo].[udf-Date-Elapsed](DateFromParts(A.BirthYearNum,A.BirthMonthNum,A.BirthDayNum),GetDate()) B

编辑 - 只读版本

Select A.Name ,B.* ,Age = concat(DateDiff(MONTH,B.DOB,GetDate())/12,'y ',DateDiff(MONTH,B.DOB,GetDate()) % 12,'m') From @YourTable A Cross Apply (Select DOB = DateFromParts(A.BirthYearNum,A.BirthMonthNum,A.BirthDayNum)) B

Answer 2

是的，它更容易保存为DOB ..但是一个简单的方法

select concat( floor(datediff(year, datefromparts(birthyearnum,birthmonthnum,birthdaynum), getdate()))-1, 'y ', datediff(month, datefromparts(birthyearnum,birthmonthnum,birthdaynum), getdate())%12, 'm')
    from #yourDates

1965年的年龄是多少41岁？

输入表：

create table #yourdates(Name varchar(10), BirthdayNum int, BirthMonthNum int, BirthYearNum int)

insert into #yourdates
(Name, BirthdayNum, BirthMonthNum, BirthYearNum) values
 ('John',      23        ,     12     ,        1965  )
,('Jane',       4        ,      9     ,        1975  )
,('Joe ',       6        ,      3     ,        1953  )

Answer 3

如果你是2008年或更小，并且不能使用datefromparts ......

declare @table table ([Name] varchar(4), BirthDayNum int, BirthMonthNum int, BirthYearNum int)
insert into @table
values
('John',23,12,1965),
('Jane',4,9,1975),
('Day',30,3,1990)

;with cte as(
    select
        [Name],
        cast(BirthYearNum as varchar(4)) + '/' + cast(BirthMonthNum as varchar(2)) + '/' + cast(BirthDayNum as varchar(2)) as DOB
    from 
        @table)

select 
     [Name]
     ,DOB
     ,datediff(year,DOB,GETDATE()) as Years
     ,datediff(month,DOB,GETDATE()) %12 as Months
     ,rtrim(cast(datediff(year,DOB,GETDATE()) as char(2))) + 'y ' + rtrim(cast(datediff(month,DOB,GETDATE()) %12 as char(2))) + 'm' as  Age 
from cte

T-SQL：计算年龄然后将字符添加到结果中

3 个答案: