我之前看过一个关于陈旧元素异常的帖子,并使用重试代码来处理它。但是,尽管将计数保持在20,但过时的元素异常仍然存在。我可以看到element2被加载到正在测试的网页中。但它仍然是作为陈旧元素的id。代码有时适用于element1。但从来没有对于element2 代码:
for (i = 1; i < 7; i++)
{
sServiceID = ExcelUtils.getCellData(i,Constant.Col_ServiceID);
System.out.println("sServiceID:"+sServiceID);
ServiceID_Filter().clear();//function returns element
ServiceID_Filter().sendKeys(sServiceID);
BaseClass.driver.manage().timeouts().implicitlyWait(10,TimeUnit.SECONDS);
Thread.sleep(3000);
ApplyFilters_element().click();
Thread.sleep(3000);
boolean result = false;
int attempts = 0;
while(attempts < 20) {
System.out.println("inside stale check loop");
BaseClass.driver.manage().timeouts().implicitlyWait(20,TimeUnit.SECONDS);
try {
if(element1.isDisplayed()||element2.isDisplayed()) //either one of the elements will be loaded
{
System.out.println("not stale "+Table_widget.ExportButton().isDisplayed());
result = true;
break;
}
} catch(StaleElementReferenceException e) {
System.out.println("stale at attempt "+attempts);
}
attempts++;
}
if(result==true)
{
if(element1.isDisplayed())
{
element3.click();
System.out.println(" button clicked");
Thread.sleep(1000);
}
else
if(element2.isDisplayed())
{ element3.click();
System.out.println("No records found");
Thread.sleep(1000);
}
}
}
答案 0 :(得分:1)
我的拙见认为问题在于:
BaseClass.driver.manage().timeouts().implicitlyWait(10,TimeUnit.SECONDS);
Thread.sleep(3000);
ApplyFilters_element().click();
Thread.sleep(3000);
首先,您使用隐式等待加线程休眠,这是灾难的一个方法。这就是造成陈旧元素异常的原因,请尝试以下内容:
public boolean waitForElement(String elementXpath, int timeOut) {
try{
WebDriverWait wait = new WebDriverWait(driver, timeOut);
boolean elementPresent=wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath(elementXpath)).isDisplayed());
System.out.printf("%nElement is present [T/F]..? ")+elementPresent;
}
catch(TimeoutException e1){e1.printStackTrace();elementPresent=false;}
return elementPresent;
}
祝你好运!