Question

是

#include <algorithm>
#include <iomanip>
#include <iostream>
#include <stdexcept>
#include <string>
#include <vector>

using std::cin;
using std::cout;
using std::domain_error;
using std::endl;
using std::istream;
using std::ostream;
using std::setprecision;
using std::sort;
using std::streamsize;
using std::string;
using std::vector;

// compute the median of a `vector<double>'
// note that calling this function copies the entire argument `vector'
double median(vector<double> vec)
{
#ifdef _MSC_VER
    typedef std::vector<double>::size_type vec_sz;
#else
    typedef vector<double>::size_type vec_sz;
#endif

    vec_sz size = vec.size();
    if (size == 0)
        throw domain_error("median of an empty vector");

    sort(vec.begin(), vec.end());

    vec_sz mid = size/2;

    return size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid];
}

// compute a student's overall grade from midterm and final exam grades and homework grade
double grade(double midterm, double final, double homework)
{
    return 0.2 * midterm + 0.4 * final + 0.4 * homework;
}

// compute a student's overall grade from midterm and final exam grades
// and vector of homework grades.
// this function does not copy its argument, because `median' does so for us.
double grade(double midterm, double final, const vector<double>& hw)
{
    if (hw.size() == 0)
        throw domain_error("student has done no homework");
    return grade(midterm, final, median(hw));
}

// read homework grades from an input stream into a `vector<double>'
istream& read_hw(istream& in, vector<double>& hw)
{
    if (in) {
        // get rid of previous contents
        hw.clear();

        // read homework grades
        double x;
        while (in >> x)
            hw.push_back(x);

        // clear the stream so that input will work for the next student
        in.clear();
    }
    return in;
}


int main()
{
    // ask for and read the student's name
    cout << "Please enter your first name: ";
    string name;
    cin >> name;
    cout << "Hello, " << name << "!" << endl;

    // ask for and read the midterm and final grades
    cout << "Please enter your midterm and final exam grades: ";
    double midterm, final;
    cin >> midterm >> final;

    // ask for the homework grades
    cout << "Enter all your homework grades, "
            "followed by end-of-file: ";

    vector<double> homework;

    // read the homework grades
    read_hw(cin, homework);

    // compute and generate the final grade, if possible
    try {
        double final_grade = grade(midterm, final, homework);
        streamsize prec = cout.precision();
        cout << "Your final grade is " << setprecision(3)
             << final_grade << setprecision(prec) << endl;
    } catch (domain_error) {
        cout << endl << "You must enter your grades.  "
            "Please try again." << endl;
        return 1;
    }

    return 0;
}

正确？我想知道他们是否会引用同一个对象。此代码无法编译。但可能有几种情况需要澄清。

我怀疑这会扩展到

test::testMethod == test::testMethod

以下是否属实。

Runnable r = () -> test.testMethod()
Runnable r1 = () -> test.testMethod()

Answer 1

让我们看看下面的例子：

Predicate<String> predicate = String::isEmpty;

Function<String,Boolean> function = String::isEmpty;

System.out.println(predicate.equals(function)); // false

lambda不包含任何有关它类型的信息。该信息是从上下文中推断出来的。正如我们在上面所看到的，相同的lamba String::inEmpty可以表示不同的功能接口。

Answer 2

即使您的代码可以编译并且test::testMethod声明为Runnable，答案test::testMethod == test::testMethod总是返回false，因为您要比较两个diff类实例。对于每个lambda表达式，编译器将为它创建一个synthentic匿名内部类。例如：

//a synthentic anonymous lambda class A implemented Runnable
Runnable r = () -> test.testMethod(); 

//a synthentic anonymous lambda class B implemented Runnable
Runnable r1 = () -> test.testMethod();

r.getClass().equals(r1.getClass());// always return false

Java双冒号运算符引用（：:)

2 个答案: