我有一个像#34; 0xFF"并希望将字符串转换为字节0xFF,因为另一个函数需要将值作为十六进制。所以像这样:
String hexstring="0xFF";
//convert to byte
byte hexbyte = (byte) 0xFF;
感谢您的帮助
答案 0 :(得分:0)
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<meta charset="utf-8" />
<title>AngularJS Plunker</title>
<script>
document.write('<base href="' + document.location + '" />');
</script>
<link rel="stylesheet" href="style.css" />
<script data-require="angular.js@1.5.x" src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.5.11/angular.min.js" data-semver="1.5.11"></script>
<script src="app.js"></script>
</head>
<body>
<div ng-controller="Ctl1">
<p>Hello {{name}}!</p>
</div>
<div ng-controller="Ctl2">
<button ng-click="changeValue()">Change Value</button>
</div>
</body>
</html>
将为您效劳
答案 1 :(得分:0)
public static byte[] asByteArray(String hex) {
// Create a byte array half the length of the string.
byte[] bytes = new byte[hex.length() / 2];
// Repeat the process for the number of elements in the byte array.
for (int index = 0; index < bytes.length; index++) {
// Convert hexadecimal string to bytes and store in array.
bytes[index] =
(byte) Integer.parseInt(
hex.substring(index * 2, (index + 1) * 2),
16);
}
// return byte array。
return bytes;
}