SELECT Name AS "Avatar Name",
COUNT(WEAPON_ID) AS "Active Weapons Held |",
SUM(W.COST) AS "Total Weapons Cost"
FROM Avatar A, Weapon_Held H, Weapon W
WHERE A.Avatar_ID=H.AVATAR_ID AND H.WEAPON_ID=W.WEAPON_ID
Group by Name;
答案 0 :(得分:3)
首先,从不在FROM
子句中使用逗号。 始终使用正确的JOIN
语法。
其次,使用表别名,但使用无处不在:
SELECT Name AS "Avatar Name",
COUNT(H.WEAPON_ID) AS "Active Weapons Held",
SUM(W.COST) AS "Total Weapons Cost"
FROM Avatar A JOIN
Weapon_Held H
ON A.Avatar_ID = H.AVATAR_ID JOIN
Weapon W
ON H.WEAPON_ID = W.WEAPON_ID
Group by Name;
答案 1 :(得分:0)
这些名为“名称”的表中是否有两个或更多列? 请使用隐式名称,如:'A.Name'或'H.Name',如:
Select A.Name....
Group by A.Name
答案 2 :(得分:0)
您收到错误是因为您的查询中有多个表具有相同的名称,并且不知道从哪里提取它。尝试将您的查询更改为以下内容:
{{1}}