Question

我为Vignere密码创建了一个加密器和解密器。加密器将它变成了“THE EAGLE已经登陆”进入“WHZ RCOOE PNU OAILRF”。但是，当我尝试使用DAVINCI解密“WHZ RCOOE PNU OAILRF”时，它并没有返回THE EAGLE已登陆。相反，它返回一个随机的混乱“ZHU EEWRE XAW RADTEH”。问题是解密Vignere还是以前的功能？我知道encryptVignere非常有效。

"""
This program will decrypt/encrypt a Vignere with the Keyword: DaVinci
"""

# helper functions
# letter to index
def letterToIndex(ch):
   alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ "
   idx = alphabet.find(ch)
   if idx < 0:
      print ("error: letter not in the alphabet", ch)
   return idx

# index to letter
def indexToLetter(idx):
   alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ "
   if idx > 25:
      print ('error: ', idx, ' is too large')
      letter = ' '
   elif idx < 0:
      print ('error: ', idx, ' is less than 0')
      letter = ' '
   else:
      letter = alphabet[idx]
   return letter

# looking up a letter in the Vignere square
def vignereIndex(keyLetter, plainTextLetter):
   keyIndex = letterToIndex(keyLetter)
   ptIndex = letterToIndex(plainTextLetter)
   newIdx = (ptIndex + keyIndex) % 26
   return indexToLetter(newIdx)

def decryptVignere(key, cipherText):
   plainText = ""
   keyLen = len(key)
   for i in range (len(cipherText)):
      ch = cipherText[i]
      if ch == ' ':
         plainText = plainText + ch
      else:
         plainText = plainText + vignereIndex(key[i%keyLen], ch)
   return plainText

#encrypting a message using the Vignere cipher
def encryptVignere(key, plainText):
   cipherText = ""
   keyLen = len(key)
   for i in range (len(plainText)):
      ch = plainText[i]
      if ch == ' ':
         cipherText = cipherText + ch
      else:
         cipherText = cipherText + vignereIndex(key[i%keyLen], ch)
   return cipherText

# decrypt
messageOne = "WHZ RCOOE PNU OAILRF" # raw_input("Enter your string: ")?
keyOne = "DAVINCI"

deStr = decryptVignere(keyOne, messageOne)
print deStr

Answer 1

您的解密方法与您的加密方法完全相同！解密方法应该相反，即减去密钥而不是添加密钥。

一种可能的解决方案是在vignereIndex方法中添加一个参数，以便在加密和解密之间切换。

def vignereIndex(keyLetter, plainTextLetter, encrypt):
    keyIndex = letterToIndex(keyLetter)
    ptIndex = letterToIndex(plainTextLetter)
    if not encrypt:
        keyIndex *= -1
    newIdx = (ptIndex + keyIndex) % 26
    return indexToLetter(newIdx)

Vignere Cipher Decryption函数不能返回正确的解密python 2.7

1 个答案: