根据其值删除数组

Question

我有这个数组：

precision

我的PHP代码：

Array
(
[0] => Array
    (
        [complet_title] => test1
        [have_background] => 0
        [condition_type] => 1
        [state] => 1
    )

[1] => Array
    (
        [complet_title] => test2
        [have_background] => 1
        [condition_type] => 1
        [state] => 0
    )
)

在foreach($a_sliders as $k => $slider){ switch($slider['condition_type']){ case 1: if($slider['state'] == 1){ if(Test::check($id, $server)){ unset($a_sliders[$k]); }else{ } } } } 我要删除包含else和condition_type = 1的子数组。有可能做到这一点吗？你能帮我吗 ？ Thx提前和抱歉我的英语

Answer 1

array_filter($array, function($v){return  ($v['condition_type'] != 1) || ($v['state'] != 0);})

Answer 2

function remove($arr, $key1, $val1, $key2, $val2){
        $foundKey = '';
        foreach($arr as $k=>$a){
            if($a[$key1] == $val1 && $a[$key2] == $val2){
                $foundKey = $k;
            }
        }
        if(isset($arr[$foundkey])){
        unset($arr[$foundkey]);
    }

return $arr;
}

现在调用删除功能：

remove($arr, 'state', '0', 'condition_type', '1');

Answer 3

像这样使用，

foreach($a_sliders as $k => $slider){
        switch($slider['condition_type']){
            case 1:
                if($slider['state'] == 1){
                    if(Test::check($id, $server)){
                        unset($a_sliders[$k]);
                    }
                }
           // your conditions are likely to be met here
                else if ($slider['state'] == 0 && $slider['condition_type'] == 1){                                
                        unset($a_sliders[$k]);
            }
        }
    }