Question

我有一个比较2个数组的函数。一个阵列由一组用户填充。另一个数组来自一个公式。它包含一个ID列表。

如果ID与公式中的任何ID匹配，则应将用户保存为＆＃34;已发布＆＃34;。如果不是，它应该与释放不匹配。

我的公式如果我检查它们，但是当它们未经检查而因此不在数组中时，它们仍然保存为已发布。这是我的代码：

    public function save_user_list(Requests $request)

    {
        $user_id_list = array();
        $counter = 0;

        if(Auth::user()->role == "owner"){
        $users = User::where('owner_id',Auth::user()->owner_id)
            ->get();
        }else{
            $users = User::where('owner_id',Auth::user()->owner_id)
                ->where('role',"user")
                ->get();
        }
        foreach($users as $user)
        {
            $user_id_list[$counter] = $user->id;
            $counter++;
        }

     for($i=0;$i<count($request->release);$i++)
        {
            $release = 0;
            for($a=0;$a<$counter;$a++)
            {
              if($request->release){

                if($request->release[$i] == $user_id_list[$a])
                {
                    $release = 1;
                }
              }
            }
            $userrelease = User::where('id',$request->release[$i])
                ->where('owner_id',Auth::user()->owner_id)
                ->first();
            if($userrelease)
            {
            $userrelease->active = $release;
            $userrelease->save();
            }
        }

        return back();

Answer 1

修正了它。只是循环问题。

    for ($a = 0; $a < $counter; $a++) {
        $release = 0;
        for ($i = 0; $i < count($request->release); $i++) {
            if ($request->release) {
                if ($request->release[$i] == $user_id_list[$a]) {
                    $release = 1;
                }
            }
        }
        $userrelease = User::where('id', $user_id_list[$a])
            ->where('owner_id', Auth::user()->owner_id)
            ->first();
        if ($userrelease && $userrelease->role != "owner") {
            $userrelease->active = $release;
            $userrelease->save();
        }
    }

设置值比较Laravel中的两个数组

1 个答案: