Question

就像我说的那样，我正在尝试使用Tweepy编写一个脚本来跟踪和基于一组关键字的RT帐户。该脚本适用于RT，但在尝试关注时会引发错误。

File "twitterraffle.py", line 19, in <module>
    api.retweet(id)
  File "/usr/local/lib/python2.7/site-packages/tweepy/binder.py", line 245, in _call
    return method.execute()
  File "/usr/local/lib/python2.7/site-packages/tweepy/binder.py", line 229, in execute
    raise TweepError(error_msg, resp, api_code=api_error_code)
tweepy.error.TweepError: [{u'message': u'You have already retweeted this tweet.', u'code': 327}]
Jakes-MacBook-Pro:mystuff jakemills$ python twitterraffle.py
Traceback (most recent call last):
  File "twitterraffle.py", line 20, in <module>
    if ('following' in result):
TypeError: argument of type 'Status' is not iterable

如果我把for循环检查我是否必须将该帐户关注到一个单独的循环中，那么原始循环可以正常工作。就在我尝试同时进行的时候。

我已在下面附上我的代码。

提前致谢。

import tweepy

consumer_key = '***'
consumer_secret = '***'
access_token = '***'
access_token_secret = '***'

auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)

api = tweepy.API(auth)


results = api.search(q="RT to win", lang="en")


i = 1

for result in results:
    if ('following' in result):
        user_id = result.user_id
        api.create_friendship(user_id)
        print 'Followed'

    id = result.id
    api.retweet(id)
    print "Retweeting %s" % i
    i = i + 1

编写一个脚本，该脚本将根据Twitter上的特定关键字自动跟踪和转换帐户，但在我尝试关注用户时收到错误

0 个答案: