Question

SELECT 
    BG_BUG_ID, BG_SUMMARY, BG_STATUS, BG_USER_14, BG_USER_39,
    BG_USER_03, BG_PROJECT, BG_DETECTED_BY, BG_USER_09
FROM 
    QC11_tests_defects_db.td.BUG
WHERE 
    BG_BUG_ID IN ('" & Replace(Mid(Tmp_List, 1, Len(Tmp_List) - 1), ";", "',')

我收到错误：

将varchar值转换为datatype int
时转换失败

我需要帮助：）

Answer 1

最佳选择是使用Tablue Valued Parameters。

首先，您需要创建一个表类型以与过程一起使用：

create type dbo.Id_udt as table (Id int not null);
go

然后，创建程序：

create procedure dbo.bug_get_fromlist (
  @Id_udt as dbo.Id_udt readonly
) as 
begin;
  set nocount, xact_abort on;

  select bg_bug_id, bg_summary, bg_status, bg_user_14, bg_user_39,
         bg_user_03, bg_project, bg_detected_by, bg_user_09
  from qc11_tests_defects_db.td.bug
  /* or use an inner join */
  where bg_bug_id in (
    select id
    from @Id_udt i
    );

end;
go

表值参数参考：

或者，您可以拆分字符串并像表格一样使用它。

在SQL Server 2016+中，您可以使用string_split()。

在2016年之前的SQL Server中，使用Jeff Moden的CSV Splitter表值函数和条件聚合：

select bg_bug_id, bg_summary, bg_status, bg_user_14, bg_user_39,
       bg_user_03, bg_project, bg_detected_by, bg_user_09
from qc11_tests_defects_db.td.bug
where bg_bug_id in (
  select s.item 
  from dbo.delimitedsplit8K(@tmp_list,';') s
  )

拆分字符串参考：

杰夫莫登

delimitedsplit8K。

create function [dbo].[delimitedsplit8K] (
      @pstring varchar(8000)
    , @pdelimiter char(1)
  )
returns table with schemabinding as
 return
  with e1(N) as (
    select 1 union all select 1 union all select 1 union all 
    select 1 union all select 1 union all select 1 union all 
    select 1 union all select 1 union all select 1 union all select 1
  )
  , e2(N) as (select 1 from e1 a, e1 b)
  , e4(N) as (select 1 from e2 a, e2 b)
  , ctetally(N) as (
    select top (isnull(datalength(@pstring),0)) 
      row_number() over (order by (select null)) from e4
  )
  , ctestart(N1) as (
    select 1 union all
    select t.N+1 from ctetally t where substring(@pstring,t.N,1) = @pdelimiter
  )
  , ctelen(N1,L1) as (
    select s.N1,
      isnull(nullif(charindex(@pdelimiter,@pstring,s.N1),0)-s.N1,8000)
    from ctestart s
  )
 select itemnumber = row_number() over(order by l.N1)
      , item       = substring(@pstring, l.N1, l.L1)
   from ctelen l
;
go

将varchar值转换为datatype int时，SQL Server错误转换失败

1 个答案: