是否可以在Delphi中将枚举值转换/转换为Integer?
如果是,那怎么样?
答案 0 :(得分:16)
这是在documentation for enumerated types明确指出的:
若干预定义函数对序数值和类型标识符进行操作。其中最重要的概述如下。
| Function | Parameter | Return value | Remarks | |----------|:-----------------------------------------------------:|----------------------------------:|---------------------------------------------------| | Ord | Ordinal expression | Ordinality of expression's value | Does not take Int64 arguments. | | Pred | Ordinal expression | Predecessor of expression's value | | | Succ | Ordinal expression | Successor of expression's value | | | High | Ordinal type identifier or variable of ordinal type | Highest value in type | Also operates on short-string types and arrays. | | Low | Ordinal type identifier or variable of ordinal type | Lowest value in type | Also operates on short-string types and arrays. |
答案 1 :(得分:8)
在我写这篇文章的时候,我看到大卫给你发了一个很好的答案,但无论如何我都会发布:
program enums;
{$APPTYPE CONSOLE}
uses
SysUtils, typinfo;
type
TMyEnum = (One, Two, Three);
var
MyEnum : TMyEnum;
begin
MyEnum := Two;
writeln(Ord(MyEnum)); // writes 1, because first element in enumeration is numbered zero
MyEnum := TMyEnum(2); // Use TMyEnum as if it were a function
Writeln (GetEnumName(TypeInfo(TMyEnum), Ord(MyEnum))); // Use RTTI to return the enum value's name
readln;
end.
答案 2 :(得分:4)
将枚举转换为整数是有效的。我无法评论其他答案,所以将此作为答案发布。转换为整数可能是一个坏主意(如果是,请评论)。
type
TMyEnum = (zero, one, two);
var
i: integer;
begin
i := integer(two); // convert enum item to integer
showmessage(inttostr(i)); // prints 2
end;
这可能类似于Ord(),但我不确定哪种是最佳做法。如果将枚举转换为整数
,上述方法也适用type
TMyEnum = (zero, one, two);
var
MyEnum: TMyEnum;
i: integer;
begin
MyEnum := two;
i := integer(MyEnum); // convert enum to integer
showmessage(inttostr(i)); // prints 2
end;
答案 3 :(得分:0)
您可以使用Ord()函数。为清楚起见,编写一对IntToEnum()和EnumToInt()函数可能更好。