Question

我正在尝试根据SSN的最后4个，姓氏和DOB来识别我的数据库中潜在的重复客户。我编写的存储过程确实识别了可能的重复项，但它将它们列在一行中 - 我试图将其拆分为单独的行以用于报告原因。

我的T-SQL看起来像：

DECLARE
@StartDate DATE = '1/1/2017',
@EndDate DATE = '3/1/2017';

SELECT  DENSE_RANK() OVER (ORDER BY c.socialSecurityNumber) AS [SSNRanking] ,
    ROW_NUMBER() OVER (PARTITION BY c.socialSecurityNumber ORDER BY c.socialSecurityNumber) AS [RowNumb] ,
    c.socialSecurityNumber AS [SSN], 
    c.id AS [CustomerID]  , 
    c.firstName AS [FirstName] ,    
    c.lastName AS [lastName] ,
    c.birthDate [birthdate] ,
    c.createDate AS [CreateDate] ,
    c2.socialSecurityNumber AS [DupSSN] ,
    c2.id AS [DupCustomerID] ,
    c2.firstName AS [DupFirstName] ,
    c2.lastName AS [DupLastName] ,
    c2.birthDate AS [DupBirthDate] ,
    c2.createDate AS [DupCreateDate]
FROM    dbo.Customers AS [c]
    INNER JOIN dbo.Customers AS [c2] ON ( SUBSTRING(c.socialSecurityNumber,6,4) = SUBSTRING(c2.socialSecurityNumber,6,4) AND c.birthDate = c2.birthDate AND c.lastName = c2.lastName AND c.id <> c2.id )
    LEFT JOIN dbo.CustomerAddresses AS [CA] ON c.id = CA.customerID             
    LEFT OUTER JOIN dbo.Common_Orders AS [co] ON co.customerID = c.id
WHERE
    c.customerStatusTypeID <> 'M'
    AND C2.customerStatusTypeID <> 'M'
    AND c.mergedTo IS NULL
    AND c2.mergedTo IS NULL
    AND CAST(co.orderDate AS DATE) >= @StartDate
    AND CAST(co.orderDate AS DATE) <= @EndDate
    AND c.id = 1234439
GROUP BY c.socialSecurityNumber ,
    c.id ,
    c.firstName ,
    c.lastName ,
    c.birthDate ,       
    c.createDate ,
    c2.socialSecurityNumber ,
    c2.id ,
    c2.firstName ,        
    c2.lastName ,
    c2.birthDate ,
    c2.createDate
ORDER BY CAST(c.socialSecurityNumber AS INT) ASC;

我的数据集如下：

SSNRanking  RowNumb  SSN        CustomerID  FirstName  lastName  birthdate  CreateDate  DupSSN     DupCustomerID  DupFirstName  DupLastName  DupBirthDate  DupCreateDate
1           1        000009915  1234439     GREG       GARRETT  1900-01-01  2014-02-25  000009915  1166084        ADAM          GARRETT      1900-01-01    2013-08-29

在这个特定的例子中，我有两个用户具有相同的最后4个SSN，相同的姓氏和相同的DOB - 但名字不同。

如何将这两个记录显示在单独的行中？理想情况下，我希望看到：

SSNRanking  RowNumb  SSN        CustomerID  FirstName  lastName  birthdate   CreateDate
1           1        000009915  1234439     GREG       GARRETT   1900-01-01  2014-02-25
1           2        000009915  1166084     ADAM       GARRETT   1900-01-01  2013-08-29

但我不确定如何在加入同一张桌子时能够做到这一点。建议？

我链接到一个脚本，该脚本创建了两个有问题的表并插入了样本数据。希望这是可以接受的：SQL Script

Answer 1

这被称为＆＃34; unpivot＆＃34;。您可以使用UNPIVOT运算符，但我更喜欢使用CROSS APPLY ... VALUES。

我将您的查询包装到CTE中，而不是详细查看它，并使用CROSS APPLY将每行分成两行。

DECLARE
@StartDate DATE = '1/1/2017',
@EndDate DATE = '3/1/2017';

WITH
CTE
AS
(
    SELECT  
        DENSE_RANK() OVER (ORDER BY c.socialSecurityNumber) AS [SSNRanking] ,
        ROW_NUMBER() OVER (PARTITION BY c.socialSecurityNumber ORDER BY c.socialSecurityNumber) AS [RowNumb] ,
        c.socialSecurityNumber AS [SSN], 
        c.id AS [CustomerID]  , 
        c.firstName AS [FirstName] ,    
        c.lastName AS [lastName] ,
        c.birthDate [birthdate] ,
        c.createDate AS [CreateDate] ,
        c2.socialSecurityNumber AS [DupSSN] ,
        c2.id AS [DupCustomerID] ,
        c2.firstName AS [DupFirstName] ,
        c2.lastName AS [DupLastName] ,
        c2.birthDate AS [DupBirthDate] ,
        c2.createDate AS [DupCreateDate]
    FROM    
        dbo.Customers AS [c]
        INNER JOIN dbo.Customers AS [c2] ON ( SUBSTRING(c.socialSecurityNumber,6,4) = SUBSTRING(c2.socialSecurityNumber,6,4) AND c.birthDate = c2.birthDate AND c.lastName = c2.lastName AND c.id <> c2.id )
        LEFT JOIN dbo.CustomerAddresses AS [CA] ON c.id = CA.customerID             
        LEFT JOIN dbo.Common_Orders AS [co] ON co.customerID = c.id
    WHERE
        c.customerStatusTypeID <> 'M'
        AND C2.customerStatusTypeID <> 'M'
        AND c.mergedTo IS NULL
        AND c2.mergedTo IS NULL
        AND CAST(co.orderDate AS DATE) >= @StartDate
        AND CAST(co.orderDate AS DATE) <= @EndDate
        AND c.id = 1234439
    GROUP BY
        c.socialSecurityNumber ,
        c.id ,
        c.firstName ,
        c.lastName ,
        c.birthDate ,       
        c.createDate ,
        c2.socialSecurityNumber ,
        c2.id ,
        c2.firstName ,        
        c2.lastName ,
        c2.birthDate ,
        c2.createDate
)
SELECT
    CA.SSNRanking
    ,CA.RowNumb
    ,CA.SSN
    ,CA.CustomerID
    ,CA.FirstName
    ,CA.lastName
    ,CA.birthdate
    ,CA.CreateDate
FROM
    CTE
    CROSS APPLY
    (
        VALUES
        (CTE.SSNRanking, CTE.RowNumb, CTE.SSN, CTE.CustomerID, CTE.FirstName, CTE.lastName, CTE.birthdate, CTE.CreateDate),
        (CTE.SSNRanking, CTE.RowNumb, CTE.DupSSN, CTE.DupCustomerID, CTE.DupFirstName, CTE.DuplastName, CTE.Dupbirthdate, CTE.DupCreateDate)
    ) AS CA(SSNRanking, RowNumb, SSN, CustomerID, FirstName, lastName, birthdate, CreateDate)
ORDER BY CAST(CA.SSN AS INT) ASC;

顺便说一下，

ROW_NUMBER() OVER (PARTITION BY ColumnA ORDER BY ColumnA)

当您按同一列进行分区和排序时，

没有意义。我不确定你想在那里实现什么。

将潜在的重复分成不同的行

1 个答案: