Question

我的查询如下：

SELECT DISTINCT TimeSched from tbl_schedule

返回此结果：

TimeSched

Rest Day
11:00 AM - 08:00 PM
No Schedule
09:00 AM - 06:00 PM
10:00 AM - 07:00 PM

当我使用ORDER BY TimeSched时，它会返回以下结果：

TimeSched

09:00 AM - 06:00 PM
10:00 AM - 07:00 PM
11:00 AM - 08:00 PM
No Schedule
Rest Day

但是，我想要的结果是默认情况下我想要第一行和第二行的“休息日”和“无日程表”，然后按升序排列日程表顺序。如下所示：

TimeSched

Rest Day
No Schedule
09:00 AM - 06:00 PM
10:00 AM - 07:00 PM
11:00 AM - 08:00 PM

Answer 1

试试这个。

select * from timetable
order by 
iif(timesched in ('No Schedule','Rest Day'),'01' + timesched,timesched)

为No Schedule和Restday添加前缀 01订购时..所以01No将去1，01R将接下来然后你的09去 24

Answer 2

如何简单地做：

SELECT DISTINCT TimeSched 
FROM tbl_schedule
ORDER BY (CASE WHEN timesched LIKE '[a-zA-Z]%' THEN 1 ELSE 0 END), 
         timesched;

Answer 3

尝试使用以下代码：

    DECLARE @TimeSched TABLE
    (ID INT IDENTITY(1,1),TimeSched VARCHAR(20))

    INSERT INTO @TimeSched
    VALUES
    ('Rest Day'),
    ('11:00 AM - 08:00 PM'),
    ('No Schedule'),
    ('09:00 AM - 06:00 PM'),
    ('10:00 AM - 07:00 PM')

    SELECT * FROM @TimeSched
    ORDER BY 
    CASE 
        WHEN TimeSched ='Rest Day' THEN 1
        WHEN TimeSched ='No Schedule' THEN 2
        ELSE 3 END

Answer 4

以下是我的问题的答案。

SELECT CASE TimeSched WHEN 'Restday' THEN 1 WHEN 'No Schedule' THEN 2 ELSE 3 END 
AS TimeSked, TimeSched ORDER BY TimeSked, TimeSched

SQL - 按时间排序，然后按开始时的文本排序

4 个答案: