所以我试图通过尝试创建一个动态的结构数组来在C中进行一些练习,但是当我尝试将结构传递给不同的函数以进行不同的操作时,我遇到了一些困难。
到目前为止我的代码:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct node {
char *str;
int len;
};
//& gives address of value, * gives value at address
int main(void) {
struct node **strarray = NULL;
int count = 0, i = 0;
printf("hello\n");
strarray = (struct node **)realloc(strarray, (count + 1) * sizeof(struct node *));
/* allocate memory for one `struct node` */
strarray[count] = (struct node *)malloc(sizeof(struct node));
strarray = init(strarray);
return 0;
}
struct node ** init(struct node ** strarray){ //this is the line that's causing problems
int i = 0, count = 0;
char line[1024];
if(fgets(line, 1024, stdin) != NULL) {
/* add ONE element to the array */
strarray = (struct node **)realloc(strarray, (count + 1) * sizeof(struct node *));
/* allocate memory for one `struct node` */
strarray[count] = (struct node *)malloc(sizeof(struct node));
/* copy the data into the new element (structure) */
strarray[count]->str = strdup(line);
strarray[count]->len = strlen(line);
count++;
return **strarray;
}
}
void printarray(){
for(i = 0; i < count; i++) {
printf("--\n");
printf("[%d]->str: %s", i, strarray[i]->str);
printf("[%d]->len: %d\n", i, strarray[i]->len);
}
}
我还没有使用printarray方法,我正在尝试获取函数声明和传递工作。目前,我正在为'init'获得一个冲突的类型 struct node ** init(struct node ** strarray) 我尝试过多次修复的错误,但没有用。
答案 0 :(得分:0)
您遇到的问题是,您需要对您返回的变量进行解除反馈。 做
return strarray
而不是
return **strarray
这是整个功能:
struct node ** init(struct node ** strarray){
int i = 0, count = 0;
char line[1024];
if(fgets(line, 1024, stdin) != NULL) {
/* add ONE element to the array */
strarray = (struct node **)realloc(strarray, (count + 1) * sizeof(struct node *));
/* allocate memory for one `struct node` */
strarray[count] = (struct node *)malloc(sizeof(struct node));
/* copy the data into the new element (structure) */
strarray[count]->str = strdup(line);
strarray[count]->len = strlen(line);
count++;
return strarray;
}
}