如何将数字从字符串中提取到单独的数组中

Question

鉴于此字符串

"In 2015, I want to know how much does iPhone 6+ cost?"

我该如何返回[2015, 6]？

我的第一次尝试是

numbers = str.tr("^0-9", '')

但是会产生20156。

Answer 1

您可以使用scan：

numbers = str.scan(/\d+/)
# => ["2015", "6"]

Answer 2

scan更好，但这也有效。

"In 2015, I want to know how much does iPhone 6+ cost?".gsub(/\D/,' ').split
  #=> ["2015", "6"]