Question

public class MyViewModel : MvxViewModel
{
   public bool MenuItemIsEnabled {
       get{return _menuItemIsEnabled;}
       set{SetProperty(ref _menuItemIsEnabled, value);
   }
}

[MvxFragment(typeof(MainViewModel), Resource.Id.content_frame, true)]
[Register(nameof(MyFragment))]
public class MyFragment : MvxFragment
{
   private Toolbar Toolbar;

   //menuitem whose enabled state should change with viewmodel property
   private IMenuItem MyMenuItem;       

   public new MyViewModel ViewModel
    {
        get { return (MyViewModel)base.ViewModel; }
        set { base.ViewModel = value; }
    }

   public override View OnCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
    {
        var view = base.OnCreateView(inflater, container, savedInstanceState);

        //we'll need the Toolbar later when we set up the IsEnabled "binding"
        Toolbar = view.FindViewById<Toolbar>(Resource.Id.toolbar);

        return view;
    }

    public override void OnViewModelSet()
    {
        base.OnViewModelSet();

        ViewModel.PropertyChanged += ViewModel_PropertyChanged;
    }

    public override void OnCreateOptionsMenu(IMenu menu, MenuInflater inflater)
    {
        base.OnCreateOptionsMenu(menu, inflater);

        //create the menu based on a menu resource
        inflater.Inflate(Resource.Menu.my_menu, menu);

        //save a reference to the menu item so we can update it when the viewmodel changes
        MyMenuItem = menu.FindItem(Resource.Id.my_menu_item);

        //set the initial enabled state based on the viewmodel
        MyMenuItem.SetEnabled(ViewModel.MenuItemIsEnabled);
    }

    private void ViewModel_PropertyChanged(object sender, System.ComponentModel.PropertyChangedEventArgs e)
    {
        //when ViewModel.MenuItemIsEnabled is updated, update the menuitem enabled state as well
        if (e.PropertyName == nameof(ViewModel.MenuItemIsEnabled ))
           BinContentsMenuItem?.SetEnabled(ViewModel.MenuItemIsEnabled);
    }
}

以上是将 test.php 文件从copy('foo/test.php', 'bar/test.php');传输到foo的代码，因此必要时会覆盖任何文件。

我正在尝试实现上述目标，但有几个未定义的目录。我该怎么做？

总体

一个位置有一堆目录（未定义的数量）
我需要将这些目录中的 test.php 文件替换为来自bar的新文件。

感谢任何帮助，谢谢！

Answer 1

如你所写，你可以在参数和循环中传递一个数组，就像那样：

function fullCopy($oldDir = '', $newDir = []) {
    foreach ($dir as $value){
        if ( is_dir($oldDir && is_dir($newDir)) ) {
            copy( $oldDir . '/test.php', $newDir . '/test.php');
        }
    }
}
fullCopy('foo', ['bar', 'bar2', 'bar3']);

如何将文件复制到多个目录，PHP？

1 个答案: