我想用SNP标记绘制核型图
它适用于函数segments
,但我想使用ggplot2包来显示优雅的图形
layout_karyogram
检查了包ggbio,但是染色体是在垂直位置绘制的。我没有找到一种方法来旋转图形,每个染色体下面都有一个名称,并在其区段旁边写下我的SNP的名称。 geom_bar
:geom_bar
:data<-data.frame(chromosome=paste0("chr", 1:4),size=c(100,400,300,200),stringsAsFactors = FALSE) dat$chromosome<-factor(dat$chromosome, levels = dat$chromosome) SNP<-data.frame(chromosome=c(1,1,2,3,3,4),Position=c(50,70,250,20,290,110),Type=c("A","A","A","B","B","B"),labels=c("SNP1","SNP2","SNP3","SNP4","SNP5","SNP6")) p <- ggplot(data=data, aes(x=chromosome, y=size)) + geom_bar( stat="identity", fill="grey70",width = .5) +theme_bw() p + geom_segment(data=SNP, aes(x=SNP$chromosome-0.2, xend=SNP$chromosome+0.2, y=SNP$Position,yend=SNP$Position,colour=SNP$Type), size=1) +annotate("text", label =SNP$labels, x =SNP$chromosome-0.5, y = SNP$Position, size = 2, colour= "red")
这里唯一的问题是,它看起来更像是一个条纹而不是染色体。我想要四肢四肢。 I found someone who got the same problem as I am
geom_path
:geom_bar
,而是使用geom_path
选项lineend = "round"
来获得四舍五入。 ggplot() + geom_path(data=NULL, mapping=aes(x=c(1,1), y=c(1,100)),size=3, lineend="round")
形状看起来很不错。所以我试着为几条染色体运行代码。
p <- ggplot() data<-data.frame(chromosome=paste0("chr", 1:4),size=c(100,400,300,200),stringsAsFactors = FALSE) for (i in 1:length(data[,1])){ p <- p + geom_path(data=NULL, mapping=aes(x=c(i,i), y=c(1,data[i,2])), size=3, lineend="round") }
它不起作用,我不知道为什么,但p只能保存最后一条染色体而不是在我的核型图中绘制四条染色体。
对这些问题的任何建议?
答案 0 :(得分:4)
我会选择geom_segment
。 SNP段的x
开始/结束是硬编码的(as.integer(chr) -+ 0.05
),否则代码非常简单。
ggplot() +
geom_segment(data = data,
aes(x = chr, xend = chr, y = 0, yend = size),
lineend = "round", color = "lightgrey", size = 5) +
geom_segment(data = SNP,
aes(x = as.integer(chr) - 0.05, xend = as.integer(chr) + 0.05,
y = pos, yend = pos, color = type),
size = 1) +
theme_minimal()
data <- data.frame(chr = paste0("chr", 1:4),
size = c(100, 400, 300, 200))
SNP <- data.frame(chr = paste0("chr", c(1, 1, 2, 3, 3, 4)),
pos = c(50, 70, 250, 20, 290, 110),
type = c("A", "A", "A", "B", "B", "B"))