Question

输入字符串：

$times = '{endTime:"2017-03-29T17:15:00.000+11:00",startTime:"2017-03-29T17:00:00.000+11:00"},{endTime:"2017-03-31T17:15:00.000+11:00",startTime:"2017-03-31T17:00:00.000+11:00"},{endTime:"2017-04-01T12:15:00.000+11:00",startTime:"2017-04-01T12:00:00.000+11:00"}';

我试图将其转换为一个看起来像这样的数组：

Array
(
    [0] => Array
        (
            endTime => "2017-03-29T17:15:00.000+11:00"
            startTime => "2017-03-29T17:00:00.000+11:00"
        )

    [1] => Array
        (
            endTime => "2017-03-31T17:15:00.000+11:00"
            startTime => "2017-03-31T17:00:00.000+11:00"
        )

    [2] => Array
        (
            endTime => "2017-04-01T12:15:00.000+11:00"
            startTime => "2017-04-01T12:00:00.000+11:00"
        )

)

我尝试过爆炸，组合和各种各样但我的代码非常混乱，以至于我确定必须有更好更清洁的方法吗？

这是 MY 最干净的起点，但即便这样也不干净，是吗？

$times = '{endTime:"2017-03-29T17:15:00.000+11:00",startTime:"2017-03-29T17:00:00.000+11:00"},{endTime:"2017-03-31T17:15:00.000+11:00",startTime:"2017-03-31T17:00:00.000+11:00"},{endTime:"2017-04-01T12:15:00.000+11:00",startTime:"2017-04-01T12:00:00.000+11:00"}';
$timesarr = explode("},{", $times);

foreach ($timesarr as $i => $item) {
    $timesarr[$i] = str_replace("{", "", $item);
    $timesarr[$i] = str_replace("}", "", $timesarr[$i]);

    $timesarr[$i] = explode(",", $timesarr[$i]);
}


echo '<pre>'; print_r($timesarr); echo '</pre>';

Answer 1

已完成改进：

starting和end附加的方括号。
将[a-zA-Z]+替换为"[a-zA-Z]+"，使其成为有效json而不是json_decode

PHP code demo

<?php

$times = '{endTime:"2017-03-29T17:15:00.000+11:00",startTime:"2017-03-29T17:00:00.000+11:00"},{endTime:"2017-03-31T17:15:00.000+11:00",startTime:"2017-03-31T17:00:00.000+11:00"},{endTime:"2017-04-01T12:15:00.000+11:00",startTime:"2017-04-01T12:00:00.000+11:00"}';
$times=$times."]";
$times="[".$times;
$jsonString=preg_replace("/([a-zA-Z]+\s*)\:/", '"$1":', $times);
print_r(json_decode($jsonString,true));

Answer 2

此代码将取代＆＃39; endTime＆＃39;与＆＃39;＆＃34; endTime＆＃34;＆＃39;和startTime相同。我不建议你这样做，但在这种情况下它会对你有用：

$times='{"endTime":"2017-03-29T17:15:00.000+11:00","startTime":"2017-03-29T17:00:00.000+11:00"},{"endTime":"2017-03-31T17:15:00.000+11:00","startTime":"2017-03-31T17:00:00.000+11:00"},{"endTime":"2017-04-01T12:15:00.000+11:00","startTime":"2017-04-01T12:00:00.000+11:00"}';
$times=str_replace("endTime",'"endTime"',$times);
$times=str_replace("startTime",'"startTime"',$times);
$times="[$times]";
echo "<h2><pre>";
print_r(json_decode($times,true));

这将输出：

Array
(
    [0] => Array
        (
            [endTime] => 2017-03-29T17:15:00.000+11:00
            [startTime] => 2017-03-29T17:00:00.000+11:00
        )

    [1] => Array
        (
            [endTime] => 2017-03-31T17:15:00.000+11:00
            [startTime] => 2017-03-31T17:00:00.000+11:00
        )

    [2] => Array
        (
            [endTime] => 2017-04-01T12:15:00.000+11:00
            [startTime] => 2017-04-01T12:00:00.000+11:00
        )

)

Answer 3

试试这个

首先使字符串成为有效的json字符串。

在开始时添加[，在结尾添加]。所以你的代码将是

$times = '[{endTime:"2017-03-29T17:15:00.000+11:00",startTime:"2017-03-29T17:00:00.000+11:00"},{endTime:"2017-03-31T17:15:00.000+11:00",startTime:"2017-03-31T17:00:00.000+11:00"},{endTime:"2017-04-01T12:15:00.000+11:00",startTime:"2017-04-01T12:00:00.000+11:00"}]';

$result = json_decode($times, true);

Answer 4

这是无效的JSON，它看起来像一堆连接在一起的JS变量。您需要一个高度自定义的解析器：

<?php
$times = '{endTime:"2017-03-29T17:15:00.000+11:00",startTime:"2017-03-29T17:00:00.000+11:00"},{endTime:"2017-03-31T17:15:00.000+11:00",startTime:"2017-03-31T17:00:00.000+11:00"},{endTime:"2017-04-01T12:15:00.000+11:00",startTime:"2017-04-01T12:00:00.000+11:00"}';
$times = str_replace(["{","}"],["\0","\0"],$times); //replace {} with null bytes (they're hopefully unique and will be used as delimiters)

$csv = str_getcsv($times,",","\0"); //Treat string as a CSV enclosed in those null bytes

$csv = array_map(function ($v) {
    $vars = explode(",",$v);
    $arr = [];
    foreach ($vars as $var) {
        $parts = str_getcsv($var,":","\""); // endTime:"2017-03-29T17:15:00.000+11:00" is like a CSV split by : and enclosed in "
        $arr[$parts[0]] = $parts[1];
    }
    return $arr;

},$csv);

print_r($csv);

结果：

Array
(
    [0] => Array
        (
            [endTime] => 2017-03-29T17:15:00.000+11:00
            [startTime] => 2017-03-29T17:00:00.000+11:00
        )

    [1] => Array
        (
            [endTime] => 2017-03-31T17:15:00.000+11:00
            [startTime] => 2017-03-31T17:00:00.000+11:00
        )

    [2] => Array
        (
            [endTime] => 2017-04-01T12:15:00.000+11:00
            [startTime] => 2017-04-01T12:00:00.000+11:00
        )

)

或者远离这个混乱，并要求将您的数据正确格式化为JSON。

PHP - 如何将多个类似JSON的字符串转换为关联数组？

4 个答案: