脚本独立运行，但在crontab中不起作用

Question

这个脚本在独立执行时运行良好，但在作为cronjob安排时失败，

 #!/bin/bash

 # TARGET TABLE COUNT FOR Server
 #
CURRENTTARGETREF=$(sqlplus -s $DB_USER/$DB_PASS << END
set pagesize 0 feedback off verify off heading off echo off;
SELECT CURRENTTARGETREF FROM PARAMETER
exit;
END
)
TABLENAME="TARGET$CURRENTTARGETREF"
TARGETCOUNT=$(sqlplus -s $DB_USER/$DB_PASS << END
set pagesize 0 feedback off verify off heading off echo off;
SELECT COUNT(*) FROM $TABLENAME
exit;
END
)
echo "Current Target table count in server: $TARGETCOUNT"
#
# COUNTER TABLE COUNT FOR server
#
S1=`echo "SELECT COUNT(*) FROM COUNTER WHERE SERVERID=1;" | sqlplus $DB_USER/$DB_PASS | sed -n '/COUNT(\*)/{n;n;p}'`
S2=`echo "SELECT COUNT(*) FROM COUNTER WHERE SERVERID=2;" | sqlplus $DB_USER/$DB_PASS | sed -n '/COUNT(\*)/{n;n;p}'`
#
echo "Current Counter table count with SERVERID '1' in server:$S1"
echo "Current Counter table count with SERVERID '2' in server:$S2"
#

下面的

是此脚本的cronjob

 31 01 * * * DS=$(date +\%Y-\%m-\%d); /path/Databasecount.sh  >> /path/test.out.$DS.txt 2>&1 

我想把脚本的输出发送到邮件，你能否请其帮助我。