Question

我创建了一个包含5列和＆＃39;好处的表格。是列之一。我可以获得整个数据，但我需要从“好处”获得前6个字母。领域。福利栏目有300多个。我的控制器代码

public function List(Request $request)
    {
        if($request->ajax()){
            $data = Package::get();  
            $list = array();
            $i=1;
            foreach ($data as $key => $Package) {
                $dd = array();
        if($Package->free_benifits != ""){

           array_push($dd, '<center>'.$Package->free_benifits.'</center>');
                }else {
                  array_push($dd, '<center>-</center>');
                }
      }

Answer 1

您可以使用substr函数剪切具有开始和长度的字符串

public function List(Request $request)
    {
        if($request->ajax()){
            $data = Package::get();  
            $list = array();
            $i=1;
            foreach ($data as $key => $Package) {
                $dd = array();
        if($Package->free_benifits != ""){
           $benifits=substr($Package->free_benifits,0,5);
           array_push($dd, '<center>'.$benifits.'</center>');
                }else {
                  array_push($dd, '<center>-</center>');
                }
      }

如何在laravel5中的SQL代码中获取字符串的六个字符？

1 个答案: