Question

我目前正在使用这种方法来自＆＃34; jeb＆＃34;处理许多变量。 BAT-file: variable contents as part of another variable

setlocal EnableDelayedExpansion
set arr[1]=17
set arr[2]=35
set arr[3]=77
(
  set idx=2
  set /a var=arr[!idx!]
  echo !var!
)

运作良好。问题是我需要再次设置一些变量的值。我的所有尝试都失败了。

set set arr[!idx!]=test
call set arr[!idx!]=test
set !arr[!idx!]!=test

Answer 1

你的问题不明确。我不明白你对＆＃34的意思;我需要再次设置一些变量的值＆＃34; 。你应该描述你的期望和你真正得到的东西。出于这个原因，我无法为您的问题提供准确答案，但只是一系列示例：

echo off
setlocal EnableDelayedExpansion

rem The target variable is "b1" or "b2", depending on *current* value of "i":
set i=1
set b1=var1
set b2=var2
call echo %%b%i%%%

rem This works, but only *outside parentheses*
set b%i%=var1changed
call echo %%b%i%%%

rem Inside paren, this works only when "i" var is not changed:
(
set b%i%=var1changed again
call echo %%b%i%%%
set i=2
set b%i%=wrong: this should be b2, but it is b1
call echo %%b%i%%%
)
set b

rem Using delayed expansion for the index works always:
(
set i=1
set b!i!=var1 again, inside paren
call echo %%b!i!%%
set i=2
set b!i!=var2changed
call echo %%b!i!%%
)
set b

输出：

var1
var1changed
var1changed again
wrong: this should be b2, but it is b1
b1=wrong: this should be b2, but it is b1
b2=var2
var1 again, inside paren
var2changed
b1=var1 again, inside paren
b2=var2changed

您也可以使用FOR /F命令进行此管理。有关详情，请访问this answer。

Answer 2

我发现（在jeb链接本身）没有任何优雅的解决方案，我仍然需要更改我的所有脚本，所以我仍在等待回复。

set i=1
set b1=var1
call echo %%b%i%%%
set b%I%=var1changed
call echo %%b%i%%%

重新定义已与另一个变量一起定义的变量的值

2 个答案: