我在laravel5.4工作。在我的视图页面中,我有一个包含状态的列表。如果is_notified为禁用,我想通过单击按钮使其启用。请告诉我最好的方法。
enter code here
@foreach($publishers as $publisher)
<ul class="list-group">
@if($publisher->pivot->is_notified===1)
<li class="list-group-item list-group-item-success">
{{$publisher->name}}<span class="pull-right">Notified</span>
</li>
@else
<li class="list-group-item list-group-item-danger">
{{$publisher->name}}<span class="pull-right">not notified</span>
</li>
@endif
</ul>
@endforeach
答案 0 :(得分:0)
1)创建一个按钮,该按钮链接到您要作为参数通知的发布商的ID。
num
2)创建路线
var num = Int()
FIRDatabase.database().reference().child("menus/Day1").observeSingleEvent(of: .value, with: {(snap) in
print(snap)
if let snapDict = snap.value as? [String:AnyObject]{
self.num = snapDict["date"] as! Int
if self.num == 5 {
print("number is 5")
else {
print("number is not 5")
}
}
})
3)在您的控制器中,即PublishersController.php,获取id
<a href="{{ url('/publisher/'.$publisher->id) }}">
<button">View Slip</button>
</a>