如何使用像pivot一样导致sql server

Question

 Insert into @temp3
 select 
 Distinct t.staffName,
    attendDate = convert(date,t.AttendDate)

  , t.staffId
  , t.Firmid
  ,t.ShiftName
  , t.attendId
  , CheckIn  = convert(time(0),t.AttendDate)
  , CheckOut = convert(time(0),x.AttendDate)
from @temp2 as t
outer  apply (
  select top 1 i.AttendDate
  from @temp2  as i
  where t.staffid = i.staffid
    and i.attendDate > t.attendDate
  order by i.attendDate desc
) x
where t.InOutMode = 'CheckIn'

[ 请检查第一张图片我想先获得CheckIn和Last Check Out

我有以下结果我想将checkIn和checkOut显示为列 喜欢

-------------------------------------------------------------------------------
atteDate  | staffName      |  staffId | Firmid |attendId | CheckIn |CheckOut |
--------------------------------------------------------------------------------
2014-11-13|Urvashi A Patel |7023     |6012 | 204 | 9:30:03 | 18:34:17

Answer 1

使用聚合查询，按attendDate的日期进行分组。

select 
    attendDate = convert(date,t.AttendDate)
  , t.staffName
  , t.staffId
  , t.Firmid
  , attendId   = min(t.attendId)
  , CheckIn    = min(convert(time(0),t.AttendDate))
  , CheckOut   = max(convert(time(0),t.AttendDate))
from t
group by 
    t.staffName
  , t.staffId
  , t.Firmid
  , convert(date,t.attendDate)

如果您收到错误，因为您尝试使用某些查询来提供上述结果，那么最好在您的问题中包含该查询。

如果是这种情况，那么使用common table expression可能有所帮助。

;with cte as (
/* query that does stuff to get the results in your question */
)

select 
    attendDate = convert(date,t.AttendDate)
  , t.staffName
  , t.staffId
  , t.Firmid
  , attendId   = min(t.attendId)
  , CheckIn    = min(convert(time(0),t.AttendDate))
  , CheckOut   = max(convert(time(0),t.AttendDate))
from t
group by 
    t.staffName
  , t.staffId
  , t.Firmid
  , convert(date,t.attendDate)