Question

我在一个文件夹中有一个numpy文件列表，我尝试从这种格式修改我的文件夹3_Traces_npy中每个文件的名称：

AES_Trace=1234_key=000102030405060708090a0b0c0d0e0f_Plaintext=f9f19b259648feb20d842480745de16f_Ciphertext=a3140be40735f9f1865aa6b1b32b5667.npy

采用以下格式：

dataArray1234_pti_f9f19b259648feb20d842480745de16f_cypher_a3140be40735f9f1865aa6b1b32b5667.npy

这可能是代码，我被阻止了如何创建nw名称：

import os
path_For_Numpy_Files='C:\\Users\\user\\3_Traces_npy'
os.chdir(path_For_Numpy_Files)
list_files_Without_Sort=os.listdir(os.getcwd())
list_files_Sorted=sorted((list_files_Without_Sort),key=os.path.getmtime)
for file in list_files_Sorted:
    new_name= 
    os.rename(os.path.join(path_For_Numpy_Files, file), os.path.join(path_For_Numpy_Files, new_name))

Answer 1

您可以使用split解析文件名字符串：

def reformat_name(filename):
    key1 = filename.split('_Plaintext=')[1].split('_Ciphertext=')[0]
    key2 = filename.split('_Ciphertext=')[1].split('.npy')[0]
    title = filename.split('AES_Trace=')[1].split('_key=')[0]
    new_filename = 'dataArray' + title + '_pti_' + key1 + '_cypher_' + key2 + '.npy'
    return new_filename

在你的for循环中调用：

for file in list_files_Sorted:
    new_name = reformat_name(file)
    os.rename(os.path.join(path_For_Numpy_Files, file), os.path.join(path_For_Numpy_Files, new_name))

如何修改numpy文件列表的名称？

1 个答案: