Question

我有一个UITextField的实例。我有键盘类型作为数字键盘，因此用户只能输入十进制值。但是我可以输入值 2.4.5.5 。请告诉我如何限制用户只能输入值2.4

Answer 1

试试这个：

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {

    if ([textField.text containsString:@"."] && [string containsString:@"."]) {
        return NO;
    } else {
        return YES;
    }
}

Answer 2

我创建了示例项目，我尝试了。我得到了确切的解决方案。请在下面查看我的答案。

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
{
    NSCharacterSet *charSet = [[NSCharacterSet characterSetWithCharactersInString:@"0123456789."] invertedSet];
    if ([string rangeOfCharacterFromSet:charSet].location != NSNotFound)
        return NO;
    else {
        NSString *newString = [textField.text stringByReplacingCharactersInRange:range withString:string];
        NSArray *arrSep = [newString componentsSeparatedByString:@"."];
        if([arrSep count] > 2)
            return NO;
        else {
            if([arrSep count] == 1) {
                if([[arrSep objectAtIndex:0] length] > 9)
                    return NO;
                else
                    return YES;
            }
            if([arrSep count] == 2) {
                if([[arrSep objectAtIndex:0] length] > 9)
                    return NO;
                else if([[arrSep objectAtIndex:1] length] > 2)  //Set after dot(.) how many digits you want.I set after dot I want 2 digits.If it goes more than 2 return NO
                    return NO;
                else {
                    if([[arrSep objectAtIndex:0] length] >= 10) //Again I set the condition here.
                        return NO;
                    else
                        return YES;
                }
            }
            return YES;
        }
    }
    return YES;
}

输出

首先，我根据条件输入带有点的9位数字。

然后我输入你的输入2.4。如果我试图给另一个点它不允许2.4。之后。

Answer 3

使用它（它对我有用）：

- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {


        NSCharacterSet *numbersOnly = [NSCharacterSet characterSetWithCharactersInString:@"0123456789."];
        NSCharacterSet *characterSetFromTextField = [NSCharacterSet characterSetWithCharactersInString:string];
        BOOL isNumbersOnly = ([numbersOnly isSupersetOfSet:characterSetFromTextField]);
        if (!isNumbersOnly) {
            return NO;
        }
        if ([string rangeOfString:@"."].location !=NSNotFound && [textField.text rangeOfString:string].location !=NSNotFound) {
            return NO;
        }

        return YES;
    }

如何在textfield中只接受一个小数点值？

3 个答案: