如何从sql表中将一行变成多行？

Question

我想问一下如何从下表中获取日期时间戳的查询：

成为这样的事情：

任何人都可以帮我解决这个问题吗？

提前致谢。

Answer 1

如果您使用的是SQL Server 2012或更高版本，那么LEAD()分析函数可以非常简单地生成您想要的结果：

SELECT employeeNo, stations_id, itemno, datetime AS [Start Shirt],
       LEAD(datetime) OVER (ORDER BY datetime) AS [End Shift]
FROM yourTable

如果运行上面的内容会导致内置函数错误，您可以尝试通过以下方式更改数据库的兼容级别：

ALTER DATABASE yourDBName
SET COMPATIBILITY_LEVEL = 110

Answer 2

尝试以下查询，它会为您提供确切的所需输出：

DECLARE @EMPLOYEE TABLE(ID INT,EMPLOYEENO VARCHAR(100),STATIONS_ID INT,ITEMNO INT,DATETIME1 DATETIME)
INSERT INTO @EMPLOYEE VALUES
(30179,'E13784',38,70077780,'3/25/2017 22:59'),
(30177,'E13784',38,70077780,'3/26/2017 22:59'),
(30173,'E13784',38,70077780,'3/27/2017 22:58')

SELECT EMPLOYEENO,STATIONS_ID,ITEMNO,DATETIME1 START_SHIFT,
(
    SELECT DATETIME1 FROM (SELECT ROW_NUMBER() OVER(ORDER BY ID DESC)SNO,*     FROM @EMPLOYEE)T2 
    WHERE T1.SNO=T2.SNO-1
)END_SHIFT
 FROM 
(SELECT ROW_NUMBER() OVER(ORDER BY ID DESC)SNO,* FROM @EMPLOYEE) T1

输出

-----------------------------------------------------------------------------
--EMPLOYEENO    STATIONS_ID ITEMNO  START_SHIFT END_SHIFT
-----------------------------------------------------------------------------
E13784  38  70077780    2017-03-25 22:59:00.000 2017-03-26 22:59:00.000
E13784  38  70077780    2017-03-26 22:59:00.000 2017-03-27 22:58:00.000
E13784  38  70077780    2017-03-27 22:58:00.000 NULL
-----------------------------------------------------------------------------