代码如下:当我调用noemail时,它返回null,出了什么问题?
那里有一个null cust_email(参见表customer),但是它只返回null,它应该返回一个cust_name,哪个部分是错误的?谢谢。
DELIMITER $$
USE a_schema_in_mysql $$
create procedure noemail()
begin
declare cust_name char;
declare custcursor cursor for
select cust_name from customers where cust_email is null;
open custcursor;
loop
fetch custcursor into cust_name;
select concat('Null email host is',cust_name) as noemailcust;
end loop;
close custcursor;
end$$
DELIMITER ;
select * from customers;
+------------+---------------+----------------------+-----------+------------+
| cust_id | cust_name | cust_address | cust_city | cust_state |
+------------+---------------+----------------------+-----------+------------+
| 1000000001 | Village Toys | 200 Maple Lane | Detroit | MI |
| 1000000002 | Kids Place | 333 South Lake Drive | Columbus | OH |
| 1000000003 | Fun4All | 1 Sunny Place | Muncie | IN |
| 1000000004 | Fun4All | 829 Riverside Drive | Phoenix | AZ |
| 1000000005 | The Toy Store | 4545 53rd Street | Chicago | IL |
+------------+---------------+----------------------+-----------+------------+
+----------+--------------+--------------------+-----------------------+
| cust_zip | cust_country | cust_contact | cust_email |
+----------+--------------+--------------------+-----------------------+
| 44444 | USA | John Smith | sales@villagetoys.com |
| 43333 | USA | Michelle Green | NULL |
| 42222 | USA | Jim Jones | jjones@fun4all.com |
| 88888 | USA | Denise L. Stephens | dstephens@fun4all.com |
| 54545 | USA | Kim Howard | kim@thetoystore.com |
+----------+--------------+--------------------+-----------------------+
以及下面的错误:
mysql> call noemail;
+-------------+
| noemailcust |
+-------------+
| NULL |
+-------------+
1 row in set (0.00 sec)
ERROR 1329 (02000): No data - zero rows fetched, selected, or processed
帮助我,谢谢你!
答案 0 :(得分:0)
我假设您可以在不使用光标的情况下实现您想要的效果
DELIMITER $$
USE a_schema_in_mysql $$
create procedure noemail()
begin
select concat('Null email host is',cust_name) from customers where cust_email is null;
end$$
DELIMITER ;
答案 1 :(得分:0)
您正在使用相同的名称" cust_name"这也是你的列名。 当参数或变量名称与字段名称冲突时,将使用参数或变量名称。
我正在添加修改内容:
DELIMITER $$
USE a_schema_in_mysql $$
create procedure noemail()
begin
declare cust_name_s char;
declare custcursor cursor for
select cust_name from customers where cust_email is null;
open custcursor;
loop
fetch custcursor into cust_name_s;
select concat('Null email host is',cust_name_s) as noemailcust;
end loop;
close custcursor;
end$$
DELIMITER ;