Question

这是我的用户模型

class User extends \yii\db\ActiveRecord
{

public static function tableName()
{
    return 'user';
}

/**
 * @inheritdoc
 */
public function rules()
{
    return [
        [[ 'created_at', 'updated_at', 'branch_id', 'postcode', 'tel_no', 'child_no','company_id'], 'integer'],
      //  [['branch_id', 'edu_level', 'date_joined','address1','country','state','city','postcode','race','position_level','religion','gender','staff_id','username','password','ic_number','tel_no','marital_status','child_no','bumi_status','resident_status','email','company_id'], 'required'],
        [['get_mail', 'gender', 'marital_status', 'resident_status', 'bumi_status','designation','status'], 'string'],
        [['date_joined'], 'safe'],
        [['staff_id', 'password', 'edu_level', 'position_level', 'address2', 'address3', 'address4', 'country', 'state', 'city', 'race', 'religion'], 'string', 'max' => 100],
        [['username', 'fullname', 'password_hash', 'password_reset_token', 'email', 'auth_key'], 'string', 'max' => 255],
        [['ic_number'], 'string', 'max' => 14],
        [['address1'], 'string', 'max' => 1000],
        [['staff_id'], 'unique'],
    ];
}

/**
 * @inheritdoc
 */
public function attributeLabels()
{
    return [
        'id' => Yii::t('user', 'ID'),
        'staff_id' => Yii::t('user', 'Staff ID'),
        'username' => Yii::t('user', 'Username'),
        'fullname' => Yii::t('user', 'Fullname'),
        'password' => Yii::t('user', 'Password'),
        'password_hash' => Yii::t('user', 'Password Hash'),
        'password_reset_token' => Yii::t('user', 'Password Reset Token'),
        'email' => Yii::t('user', 'Email'),
        'ic_number' => Yii::t('user', 'Ic Number'),
        'auth_key' => Yii::t('user', 'Auth Key'),
        'status' => Yii::t('user', 'Status'),
        'created_at' => Yii::t('user', 'Created At'),
        'updated_at' => Yii::t('user', 'Updated At'),
        'company_id' => Yii::t('user', 'Company'),
        'branch_id' => Yii::t('user', 'Branch'),
        'edu_level' => Yii::t('user', 'Education Level'),
        'position_level' => Yii::t('user', 'Position Level'),
        'designation' => Yii::t('user', 'Designation'),
        'get_mail' => Yii::t('user', 'Get Mail'),
        'date_joined' => Yii::t('user', 'Date Joined'),
        'gender' => Yii::t('user', 'Gender'),
        'address1' => Yii::t('user', 'Address1'),
        'address2' => Yii::t('user', 'Address2'),
        'address3' => Yii::t('user', 'Address3'),
        'address4' => Yii::t('user', 'Address4'),
        'country' => Yii::t('user', 'Country'),
        'state' => Yii::t('user', 'State'),
        'city' => Yii::t('user', 'City'),
        'postcode' => Yii::t('user', 'Postcode'),
        'tel_no' => Yii::t('user', 'Tel No'),
        'marital_status' => Yii::t('user', 'Marital Status'),
        'child_no' => Yii::t('user', 'Child No'),
        'race' => Yii::t('user', 'Race'),
        'religion' => Yii::t('user', 'Religion'),
        'resident_status' => Yii::t('user', 'Resident Status'),
        'bumi_status' => Yii::t('user', 'Bumi Status'),
    ];
}

public static function find()
{
    return new UserQuery(get_called_class());
}

public function getCountries()
{
    return $this->hasOne(Countries::classname(),['id'=>'country']);
}

public function getStates()
{
    return $this->hasOne(States::classname(),['id'=>'state']);
}

public function getNext_of_kin()
{
    return $this->hasMany(NextOfKin::classname(),['staff_id'=>'staff_id']);
}

}

这是我的视图控制器

 public function actionView($staff_id)
{   
        $request = Yii::$app->request;
        $model = $this->findModel($staff_id);
        $model2 = $model ->next_of_kin;
        //$sql = "SELECT next_of_kin.name AS Name FROM user left join next_of_kin ON next_of_kin.staff_id = user.staff_id";

         $dataProvider = new ActiveDataProvider([
        'query' => User::find() ->joinWith(['next_of_kin'])-> where(['next_of_kin.staff_id' => $staff_id]),
    ]); 

    if($request->isAjax)
        {
            Yii::$app->response->format = Response::FORMAT_JSON;

            return [
                    'title'=> "User #".$staff_id,
                    'content'=>$this->renderAjax('view', [
                        'model' => $model,
                        'dataProvider' => $dataProvider,
                    ]),
                    'footer'=> Html::button('Close',['class'=>'btn btn-default pull-left','data-dismiss'=>"modal"]).
                            Html::a('Edit',['update','staff_id'=>$staff_id],['class'=>'btn btn-primary','role'=>'modal-remote'])
                ];    
        }
        else
        {
            return $this->render('view', [
               'model' => $model,
                'dataProvider' => $dataProvider,
                "size" => "modal-lg",
            ]);
        }
}

这是视图文件

[
                'label' => 'Next of Kin Details',
                'content' => GridView::widget([
                        'dataProvider' => $dataProvider,
                        'columns' => [
                          ['class' => 'yii\grid\SerialColumn'],
                            'username',
                            'fullname',
                            'staff_id',
                            'next_of_kin.name',
                    ],
                ]),  
            ],

我试图根据User表中的staff id从表next_of_kin获取名称。但是当我试图查看它时，它会显示未设置

Answer 1

为什么在想要使用单个表/关系加入时使用数组，我的意思是它不应该是错误的，但它令人困惑。您的查询似乎没有错，请查找调试器的数据库模块，以查看Yii AR组成的实际查询，并以原始格式在DB中运行它。查询本身并没有被破坏，至少从我所知道的，数据库架构，你可以查询没有任何东西返回的staff_id，你传递$ staff_id的方式以及其他一些东西可能被打破这一事实。

Answer 2

activeDataProvider返回模型集合

您可以从dataProvider

中检索模型数组

  $myModels = $dataProvider->getModels();

例如：获取第一个元素（用户模型）next_of_kin模型

  $my_next_of_kin = $myModels[0]->next_of_kin;

迭代模型以获取值;

  foreach ($my_next_of_kin as $key => $value) {
    echo $value->your_next_of_kin_col;
  }

Answer 3

它只适用于一对一的关系！你有一对多。

public function getNext_of_kin()
{
    return $this->hasMany(NextOfKin::classname(),['staff_id'=>'staff_id']);
}

'columns' => [
       ['class' => 'yii\grid\SerialColumn'],
       'username',
       'fullname',
       'staff_id',
       'next_of_kin.name', // "next_of_kin" should be one-to-one relation
],

yii2 ActiveData Provider

3 个答案: