Question

这是完整的方法。之后我使用了第二种方法GetSQLiteDatabaseRecords（）;用于在edittext中显示结果。 + value_spinner +和+ date_value +是分别存储来自微调器和按钮的值的字符串。

    GetSQliteQuery = "SELECT * FROM attendance where name ='"+value_spiner+"'AND date='"+date_value+"'";
 _db = openOrCreateDatabase("employee.db", Context.MODE_PRIVATE, null);

        cursor = _db.rawQuery(GetSQliteQuery, null);
        if (cursor != null&& cursor.moveToFirst()){
            // cursor.moveToFirst();
            GetSQLiteDatabaseRecords();
        }else{
            Toast.makeText(Lunch_timeout.this, "No match", Toast.LENGTH_SHORT).show();
        }
private void GetSQLiteDatabaseRecords()
{
    in_time.setText(cursor.getString(3).toString());
}

我也是这样使用过的。 `

cursor=_db.query(true, mydb.TABLE_Attendance, new String[] {
                        mydb.ATT_COL_4,},
               mydb.ATT_COL_2 + "=?" + " and "  +
                        mydb.ATT_COL_3 + "=?",
                new String[] {value_spiner,date_value},
                null, null, null , null);

            if ( cursor.moveToFirst()){
                do {
                    GetSQLiteDatabaseRecords();
                }while (cursor.moveToNext());
        }else{
            Toast.makeText(Lunch_timeout.this, "No match", Toast.LENGTH_SHORT).show();
        }`

Answer 1

试试这个 -

GetSQliteQuery = "SELECT * FROM attendance where name ='"+value_spiner+"' AND date='"+date_value+"'";

选择带AND条件的查询不起作用。'“+ value_spinner +”'和'“+ date_value +”'都是字符串

1 个答案: