传递POST请求。 Spting安全性。休息模板。 Jackson转换器

时间:2017-03-26 12:52:04

标签: java android json spring jackson

我在Spring框架中更好,我想问你一个问题。 我是否通过正确的POST请求在我的用户DB中注册。

我有一个Android客户端,我找到了如何使用网络服务的唯一方法。 我正在使用AsyncTask来管理请求。

但我不知道如何使用我的User课程发送POST请求以在数据库中注册他。 已完成数据库的逻辑。

我要求您帮助我如何发布请求以及如何在服务器上管理他。

所以这是我的代码:

服务器端,用户控制器:

@RestController
@RequestMapping("/user")
public class UserController {

    @Autowired
    private UserService userService;

    @Autowired
    private SecurityService securityService;

    @Autowired
    private UserValidator userValidator;


    @RequestMapping(value = "/registration", method = RequestMethod.POST)
    @ResponseBody
    public User registration(@RequestBody User user, BindingResult bindingResult, Model model) {
        userValidator.validate(user, bindingResult);// here is validate logic
        if (bindingResult.hasErrors()) {
            //What should i return here to my Android client ?
        }
        userService.save(user);
        securityService.autoLogin(user.getUserName(), user.getConfirmPassword());
        return user;
    }

    @RequestMapping(value = "/login", method = RequestMethod.GET)
    public String login(Model model, String error, String logout) {
        if (error != null) {
            model.addAttribute("error", "Username or password is incorrect.");
        }

        if (logout != null) {
            model.addAttribute("message", "Logged out successfully.");
        }

        return "login";// what should I return to the client ???
        //How my android client will understand that user is loged in ?
    }
}

接下来我有客户端(这里有一些MVP逻辑,但是nvm):

public class CreateAccountPresenter implements CreateAccountContract.Presenter {
    private CreateAccountContract.View view;
    private String userName;
    private String userPassword;
    private String confirmUserPassword;


    public CreateAccountPresenter(CreateAccountContract.View view) {
        this.view = view;
    }

    @Override
    public void onCreateAccountClick() {
        userName = view.getUserName();
        userPassword = view.getPassword();
        confirmUserPassword = view.getPasswordConfirmation();
        new CreateAccountTask().execute();

    }

    private class CreateAccountTask extends AsyncTask<Void, Void, User>{
        // How do I properly pass the post request with my User object ?
        @Override
        protected User doInBackground(Void... voids) {
            RestTemplate restTemplate = new RestTemplate();
            restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
            User user = new User(userName, userPassword, confirmUserPassword);
            return restTemplate.postForObject(URL.getUserRegistration(), user, User.class);
        }

        @Override
        protected void onPostExecute(User user) {
            view.makeToast("User registration complited " + user.getUserName());
        }
    }

}

我是否需要在客户端初始化转换器? 如果您要在评论中发布一些代码,那么请求帮助也很棒。

更新 我改变了一点客户端代码,现在我在客户端获得了下一个错误:

W/RestTemplate: POST request for "http://192.168.0.80:8080/user/registration" resulted in 400 (Bad Request); invoking error handler
E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1
                  Process: com.example.user.userauthorisation, PID: 4676
                  java.lang.RuntimeException: An error occured while executing doInBackground()
                      at android.os.AsyncTask$3.done(AsyncTask.java:300)
                      at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355)
                      at java.util.concurrent.FutureTask.setException(FutureTask.java:222)
                      at java.util.concurrent.FutureTask.run(FutureTask.java:242)
                      at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
                      at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
                      at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
                      at java.lang.Thread.run(Thread.java:818)
                   Caused by: org.springframework.web.client.HttpClientErrorException: 400 Bad Request
                      at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:88)
                      at org.springframework.web.client.RestTemplate.handleResponseError(RestTemplate.java:585)
                      at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:541)
                      at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:499)
                      at org.springframework.web.client.RestTemplate.postForObject(RestTemplate.java:348)
                      at com.example.user.userauthorisation.createaccount.CreateAccountPresenter$CreateAccountTask.doInBackground(CreateAccountPresenter.java:42)
                      at com.example.user.userauthorisation.createaccount.CreateAccountPresenter$CreateAccountTask.doInBackground(CreateAccountPresenter.java:35)
                      at android.os.AsyncTask$2.call(AsyncTask.java:288)
                      at java.util.concurrent.FutureTask.run(FutureTask.java:237)
                      at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231) 
                      at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112) 
                      at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587) 
                      at java.lang.Thread.run(Thread.java:818) 
W/EGL_emulation: eglSurfaceAttrib not implemented
W/OpenGLRenderer: Failed to set EGL_SWAP_BEHAVIOR on surface 0xeb89dde0, error=EGL_SUCCESS

在服务器端:

2254021 [http-apr-8080-exec-2] WARN org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver - Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Could not read document: Unrecognized field "confirmationPassword" (class com.webserverconfig.user.entity.User), not marked as ignorable (4 known properties: "id", "confirmPassword", "userName", "userPassword"])
 at [Source: java.io.PushbackInputStream@2cbfcb7c; line: 1, column: 26] (through reference chain: com.webserverconfig.user.entity.User["confirmationPassword"]); nested exception is com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "confirmationPassword" (class com.webserverconfig.user.entity.User), not marked as ignorable (4 known properties: "id", "confirmPassword", "userName", "userPassword"])
 at [Source: java.io.PushbackInputStream@2cbfcb7c; line: 1, column: 26] (through reference chain: com.webserverconfig.user.entity.User["confirmationPassword"])

请帮忙吗?

1 个答案:

答案 0 :(得分:0)

您没有共享User bean,但错误日志显示您尝试访问字段confirmationPassword,而只有confirmPassword。检查bean的getter名称。