我在Spring框架中更好,我想问你一个问题。 我是否通过正确的POST请求在我的用户DB中注册。
我有一个Android客户端,我找到了如何使用网络服务的唯一方法。 我正在使用AsyncTask来管理请求。
但我不知道如何使用我的User
课程发送POST请求以在数据库中注册他。
已完成数据库的逻辑。
我要求您帮助我如何发布请求以及如何在服务器上管理他。
所以这是我的代码:
服务器端,用户控制器:
@RestController
@RequestMapping("/user")
public class UserController {
@Autowired
private UserService userService;
@Autowired
private SecurityService securityService;
@Autowired
private UserValidator userValidator;
@RequestMapping(value = "/registration", method = RequestMethod.POST)
@ResponseBody
public User registration(@RequestBody User user, BindingResult bindingResult, Model model) {
userValidator.validate(user, bindingResult);// here is validate logic
if (bindingResult.hasErrors()) {
//What should i return here to my Android client ?
}
userService.save(user);
securityService.autoLogin(user.getUserName(), user.getConfirmPassword());
return user;
}
@RequestMapping(value = "/login", method = RequestMethod.GET)
public String login(Model model, String error, String logout) {
if (error != null) {
model.addAttribute("error", "Username or password is incorrect.");
}
if (logout != null) {
model.addAttribute("message", "Logged out successfully.");
}
return "login";// what should I return to the client ???
//How my android client will understand that user is loged in ?
}
}
接下来我有客户端(这里有一些MVP逻辑,但是nvm):
public class CreateAccountPresenter implements CreateAccountContract.Presenter {
private CreateAccountContract.View view;
private String userName;
private String userPassword;
private String confirmUserPassword;
public CreateAccountPresenter(CreateAccountContract.View view) {
this.view = view;
}
@Override
public void onCreateAccountClick() {
userName = view.getUserName();
userPassword = view.getPassword();
confirmUserPassword = view.getPasswordConfirmation();
new CreateAccountTask().execute();
}
private class CreateAccountTask extends AsyncTask<Void, Void, User>{
// How do I properly pass the post request with my User object ?
@Override
protected User doInBackground(Void... voids) {
RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());
User user = new User(userName, userPassword, confirmUserPassword);
return restTemplate.postForObject(URL.getUserRegistration(), user, User.class);
}
@Override
protected void onPostExecute(User user) {
view.makeToast("User registration complited " + user.getUserName());
}
}
}
我是否需要在客户端初始化转换器? 如果您要在评论中发布一些代码,那么请求帮助也很棒。
更新 我改变了一点客户端代码,现在我在客户端获得了下一个错误:
W/RestTemplate: POST request for "http://192.168.0.80:8080/user/registration" resulted in 400 (Bad Request); invoking error handler
E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1
Process: com.example.user.userauthorisation, PID: 4676
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:300)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:355)
at java.util.concurrent.FutureTask.setException(FutureTask.java:222)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:818)
Caused by: org.springframework.web.client.HttpClientErrorException: 400 Bad Request
at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:88)
at org.springframework.web.client.RestTemplate.handleResponseError(RestTemplate.java:585)
at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:541)
at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:499)
at org.springframework.web.client.RestTemplate.postForObject(RestTemplate.java:348)
at com.example.user.userauthorisation.createaccount.CreateAccountPresenter$CreateAccountTask.doInBackground(CreateAccountPresenter.java:42)
at com.example.user.userauthorisation.createaccount.CreateAccountPresenter$CreateAccountTask.doInBackground(CreateAccountPresenter.java:35)
at android.os.AsyncTask$2.call(AsyncTask.java:288)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
at java.lang.Thread.run(Thread.java:818)
W/EGL_emulation: eglSurfaceAttrib not implemented
W/OpenGLRenderer: Failed to set EGL_SWAP_BEHAVIOR on surface 0xeb89dde0, error=EGL_SUCCESS
在服务器端:
2254021 [http-apr-8080-exec-2] WARN org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver - Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Could not read document: Unrecognized field "confirmationPassword" (class com.webserverconfig.user.entity.User), not marked as ignorable (4 known properties: "id", "confirmPassword", "userName", "userPassword"])
at [Source: java.io.PushbackInputStream@2cbfcb7c; line: 1, column: 26] (through reference chain: com.webserverconfig.user.entity.User["confirmationPassword"]); nested exception is com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "confirmationPassword" (class com.webserverconfig.user.entity.User), not marked as ignorable (4 known properties: "id", "confirmPassword", "userName", "userPassword"])
at [Source: java.io.PushbackInputStream@2cbfcb7c; line: 1, column: 26] (through reference chain: com.webserverconfig.user.entity.User["confirmationPassword"])
请帮忙吗?
答案 0 :(得分:0)
您没有共享User
bean,但错误日志显示您尝试访问字段confirmationPassword
,而只有confirmPassword
。检查bean的getter名称。