Question

我在组合这两个陈述方面遇到了麻烦。

我有一个festivalTable你可以在=＆gt;上投票voteTable。对于特殊场合，您还可以拥有specialVoteTable

对于我有的2个单独的表：

select festivalId as festId, COUNT(festivalId) as total from Vote 
where active = 'J'  and FestivalId = 593
group by FestivalId

另一张表相同。现在我需要结合这两个结果，除了从特殊投票我需要将它乘以8，所以我可以将总数除以9。

所以2个单独的查询是

select festivalId as festId, COUNT(festivalId) as total from Vote 
where active = 'J'  and FestivalId = 593
group by FestivalId

select festivalId as festId, (COUNT(festivalId) * 8) as total from       SpecialChartVote 
where active = 'J'  and FestivalId = 593
group by FestivalId

（尚未与festivalTable合并。）

有道理吗？

Answer 1

在子查询中使用union all：

select festId, sum(total)/9 as total
from 
  (
  select 
      festivalId as festId
    , COUNT(festivalId) as total 
  from Vote 
  where active = 'J'  and FestivalId = 593
  group by FestivalId
  union all 
  select 
      festivalId as festId
    , (COUNT(festivalId) * 8) as total 
  from SpecialChartVote 
  where active = 'J'  and FestivalId = 593
  group by FestivalId
  ) u
group by festId

Answer 2

您的查询，正如所写，只是在寻找一个节日。这看起来很奇怪，但您可以通过执行以下操作来组合查询：

select 593 as festId,
       ( (select count(*) from Vote where active = 'J'  and FestivalId = 593) +
         (select count(*) * 8 from SpecialChartVote where active = 'J' and FestivalId = 593)
       ) / 9.0

如果你想获得多个节日的信息，那么SQLZims答案肯定会更好。我只想指出您可以通过执行以下操作“合并”您的查询：

select (<query1> + <query2>)

sql语句结合计数2语句结果

2 个答案: