我想将应用程序的映射根路径发送到特定的控制器。以下是我这样做的方式:
我的控制器:
@Controller
public class Index {
@RequestMapping(value = "/", method = RequestMethod.GET)
public String indexPage(ModelMap model, @CookieValue(value = "cityName", defaultValue = "beijing") String cityNameCookie, HttpServletRequest request) {
String cityName = CookieTools.setCityNameValue(request, cityNameCookie);
model.addAttribute("cityName", cityName);
System.out.println("index");
return "index";
}
}
我的web.xml:
<web-app ...>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>springmvc</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springmvc</servlet-name>
<url-pattern>/</url-pattern>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
</web-app>
当我进入localhost:8080时,控制器未按预期执行。
我尝试将@RequestMapping(value = "/", method = RequestMethod.GET)
更改为@RequestMapping(value = "/abc", method = RequestMethod.GET)
,并输入localhost:8080 / abc,控制器按预期执行。
所以我认为问题在于@requestMapping值属性的语法。
所以,我的问题是如何使用requestMapping映射根路径?
我搜索了相对关键字但没有找到任何内容。
答案 0 :(得分:0)
请将@RequestMapping(value =&#34; /&#34;)注释添加到控制器,然后尝试。
以下是我的工作示例,
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
@RequestMapping("/")
public class HelloController {
@RequestMapping(method = RequestMethod.GET)
public String printWelcome(ModelMap model) {
model.addAttribute("message", "Spring MVC Hello World");
return "hello";
}
}
Spring config,
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.mkyong.common.controller" />
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix">
<value>/WEB-INF/pages/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>
的web.xml
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring Web MVC Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
</web-app>
答案 1 :(得分:0)
解决。请参阅Spring welcome-file-list correct mapping
的第一个答案添加
int main()
{
int m,n;
scanf("%d%d",&m,&n);
int a[m][n];
foo(a,m,n);
return 0;
}
到我的web.xml。
为我工作。