size_t writeFunctionHandler(char *contents,size_t size,size_t nmemb,void *userdata) {
// size of the storedSize
static size_t storedSize = 0;
// the size of data available
size_t realSize = size * nmemb;
char *dataBuffer = (char *) userdata;
// realloc the buffer buffer
dataBuffer = realloc(dataBuffer,storedSize + realSize);
if (dataBuffer == NULL) {
printf("Could not allocate memory \n");
return 0;
}
// store the contents of realSize from last storedSize
memcpy(&(dataBuffer[storedSize]),contents,realSize);
storedSize += realSize;
return realSize;
}
我无法理解为什么上面的代码返回并且错误指针被重新分配&#d; d未分配
当我使用此示例代码时
struct MemoryStruct {
char *memory;
};
size_t writeFunctionHandler(char *contents,size_t size,size_t nmemb, void *userdata) {
size_t realSize = size * nmemb;
static size_t storedSize = 0;
//char *dataBuffer = (char *)userdata;
struct MemoryStruct *chunk = (struct MemoryStruct *)userdata;
printf("print 1\n");
chunk -> memory = realloc(chunk -> memory,storedSize + realSize);
printf("print 2\n");
if (chunk -> memory == NULL) {
printf("Could not allocate memory\n");
return 0;
}
memcpy(&(chunk -> memory[storedSize]),contents,realSize);
storedSize += realSize;
printf("print 3\n");
return realSize;
}
一切似乎都运转正常。
以上是卷曲 writeFunctionHandler
int main() {
char *buffer = calloc(1,1);
// struct MemoryStruct chunk;
// chunk.memory = calloc(1,1);
CURL *curl = curl_easy_init();
curl_easy_setopt(curl, CURLOPT_URL, "http://stackoverflow.com");
curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, writeFunctionHandler);
curl_easy_setopt(curl, CURLOPT_WRITEDATA, (void *)buffer);
// curl_easy_setopt(curl,CURLOPT_WRITEDATA, (void *) &chunk);
free(buffer);
//free(chunk.memory);
curl_easy_cleanup(curl);
return 0;
}
我无法理解2代码之间的区别,除了我在后面的情况下使用struct
的事实。
答案 0 :(得分:3)
关键是userdata
指向包含成员memory
的struct,它是从堆中分配的成员。
此外,当函数返回时,memory
可能已使用realloc更改,但在您的版本中,无法在函数外部看到更改。那是因为指针的值被传递,而不是地址。如果地址已通过(即void **userdata
),您将重新分配到该地址(即*userdata= realloc(..
),并且它将在函数外部显示。