Question

我需要合并一系列词典：

update ShareButton 
set TotalShare = (sum(Share) from SharePage where "ShareButtonID" = ShareButtonID of updated/inserted record)) 
where ID = ShareButtonID of updated/inserted record)`

我可以使用此功能：

dict1 = {u'electronica ': 12.0, u'art rock ': 14.0, u'chillout ': 12.0, u'genius ': 14.0, u'trip-hop ': 11.0, u'psychedelic ': 12.0, u'indie pop ': 11.0, u'ambient ': 12.0, u'indie rock ': 15.0, u'post-rock ': 11.0, u'alternative rock ': 15.0, u'seen live ': 12.0, u'melancholic ': 14.0, u'Awesome ': 15.0, u'radiohead ': 19.0, u'emo ': 10.0, u'rock ': 16.0, u'indie ': 13.0, u'90s ': 5.0, u'pop ': 12.0, u'britpop ': 13.0, u'british ': 17.0, u'classic rock ': 12.0, u'better than radiohead ': 12.0, u'overrated ': 12.0, u'alternative ': 14.0, u'Progressive ': 13.0, u's ': 7.0, u'Favorite ': 12.0, u'electronic ': 13.0, u'Experimental Rock ': 13.0, u'beautiful ': 14.0, u'melancholy ': 14.0, u'idm ': 12.0, u'Progressive rock ': 12.0, u'favorites ': 12.0, u'english ': 12.0, u'male vocalists ': 13.0, u'experimental ': 12.0, u'UK ': 14.0}
dict2 = {u'west coast': 26.0, u'hip hop': 24.0, u'rap': 19.0, u'gansta rap': 24.0}
dict3 = {u'hip hop': 26.0, u'west coast': 28.0, u'rap': 21.0, u'gansta rap': 26.0}
dict4 = {u'electronica ': 53.0, u'art rock ': 55.0, u'chillout ': 53.0, u'90s ': 5.0, u'trip-hop ': 52.0, u'psychedelic ': 53.0, u'ambient ': 53.0, u'Awesome ': 56.0, u'post-rock ': 52.0, u'alternative rock ': 56.0, u'seen live ': 53.0, u'melancholic ': 55.0, u'indie rock ': 56.0, u'melancholy ': 55.0, u'male vocalists ': 54.0, u'alternative ': 55.0, u'rock ': 57.0, u'indie ': 54.0, u'genius ': 55.0, u'pop ': 53.0, u'britpop ': 54.0, u'british ': 58.0, u'classic rock ': 53.0, u'better than radiohead ': 53.0, u'overrated ': 53.0, u'emo ': 51.0, u'Progressive ': 54.0, u's ': 48.0, u'Favorite ': 53.0, u'electronic ': 54.0, u'Experimental Rock ': 54.0, u'beautiful ': 55.0, u'radiohead ': 60.0, u'idm ': 53.0, u'Progressive rock ': 53.0, u'favorites ': 53.0, u'english ': 53.0, u'indie pop ': 52.0, u'experimental ': 53.0, u'UK ': 55.0}

然后我会忘记重复的def merge_dicts(*dict_args): result = {} for dictionary in dict_args: result.update(dictionary) return result（在例子中经常发生）。

相反，我必须合并keys添加重复dicts的{{1}}，因为此处values为keys。

我该如何实现？

Answer 1

我会使用collections.Counter：

In [9]: ds = [dict1, dict2, dict3, dict4]

In [10]: from collections import Counter

In [11]: result = Counter()

In [12]: for d in ds:
    ...:     result.update(d)
    ...:

结果：

In [13]: result
Out[13]:
Counter({'90s ': 10.0,
         'Awesome ': 71.0,
         'Experimental Rock ': 67.0,
         'Favorite ': 65.0,
         'Progressive ': 67.0,
         'Progressive rock ': 65.0,
         'UK ': 69.0,
         'alternative ': 69.0,
         'alternative rock ': 71.0,
         'ambient ': 65.0,
         'art rock ': 69.0,
         'beautiful ': 69.0,
         'better than radiohead ': 65.0,
         'british ': 75.0,
         'britpop ': 67.0,
         'chillout ': 65.0,
         'classic rock ': 65.0,
         'electronic ': 67.0,
         'electronica ': 65.0,
         'emo ': 61.0,
         'english ': 65.0,
         'experimental ': 65.0,
         'favorites ': 65.0,
         'gansta rap': 50.0,
         'genius ': 69.0,
         'hip hop': 50.0,
         'idm ': 65.0,
         'indie ': 67.0,
         'indie pop ': 63.0,
         'indie rock ': 71.0,
         'male vocalists ': 67.0,
         'melancholic ': 69.0,
         'melancholy ': 69.0,
         'overrated ': 65.0,
         'pop ': 65.0,
         'post-rock ': 63.0,
         'psychedelic ': 65.0,
         'radiohead ': 79.0,
         'rap': 40.0,
         'rock ': 73.0,
         's ': 55.0,
         'seen live ': 65.0,
         'trip-hop ': 63.0,
         'west coast': 54.0})

或者，如果您不使用Counter：

In [14]: result = {}

In [15]: for d in ds:
    ...:     for k in d:
    ...:         result[k] = result.get(k, 0) + d[k]
    ...:

In [16]: result
Out[16]:
{'90s ': 10.0,
 'Awesome ': 71.0,
 'Experimental Rock ': 67.0,
 'Favorite ': 65.0,
 'Progressive ': 67.0,
 'Progressive rock ': 65.0,
 'UK ': 69.0,
 'alternative ': 69.0,
 'alternative rock ': 71.0,
 'ambient ': 65.0,
 'art rock ': 69.0,
 'beautiful ': 69.0,
 'better than radiohead ': 65.0,
 'british ': 75.0,
 'britpop ': 67.0,
 'chillout ': 65.0,
 'classic rock ': 65.0,
 'electronic ': 67.0,
 'electronica ': 65.0,
 'emo ': 61.0,
 'english ': 65.0,
 'experimental ': 65.0,
 'favorites ': 65.0,
 'gansta rap': 50.0,
 'genius ': 69.0,
 'hip hop': 50.0,
 'idm ': 65.0,
 'indie ': 67.0,
 'indie pop ': 63.0,
 'indie rock ': 71.0,
 'male vocalists ': 67.0,
 'melancholic ': 69.0,
 'melancholy ': 69.0,
 'overrated ': 65.0,
 'pop ': 65.0,
 'post-rock ': 63.0,
 'psychedelic ': 65.0,
 'radiohead ': 79.0,
 'rap': 40.0,
 'rock ': 73.0,
 's ': 55.0,
 'seen live ': 65.0,
 'trip-hop ': 63.0,
 'west coast': 54.0}

Answer 2

在Python Dict中你不允许给出重复的密钥。如果你第二次给出相同的密钥，那么系统将用第二个值覆盖第一个值。

一个解决方案是您需要创建值列表。

ex：{key：[value，value，value]}

您可以从以下链接找到最佳示例。

List of values for duplicate keys in dictionary Python

Python - 合并字典，添加重复键的值

2 个答案: