Question

我在使用Python编写基本数字猜谜游戏的代码时遇到了麻烦。游戏的目的是正确猜出程序随机挑选的1到10的数字。我还提供了一些帮助文本，告诉用户他们是否猜到太高或太低。我一直收到语法错误。这是我到目前为止写的代码：

 print "Welcome to the number guessing game"
 print "I have my number..."
 import random
 while True:

    random.randint(1, 10)
    number = raw_input("What is your guess[1-10]: ")
    if number > random.radint(1, 10):
         print "sorry you guessed to high"
    elif number < random.radint(1, 10):
         print "You guessed to low"
    elif number == random.radint(1, 10):
         print "You guessed right thanks for playing"
         break
    else: raw_input("What is your guess[1-10]: ")

Answer 1

randint不是radint。您正在为每个测试创建一个新的随机数;你应该为while循环之外的随机数分配一个变量。

r = random.randint(1, 10)

您必须缩进if: else:块 - Python对布局非常敏感，例如

if number > r:
    print "sorry you guessed to high"

您正在与str进行比较，需要将输入转换为int()。

number = int(raw_input("What is your guess[1-10]: "))

最后你有一个不必要的else:条件所以把它们放在一起：

import random
print "Welcome to the number guessing game"
print "I have my number..."
r = random.randint(1, 10)
while True:
    number = int(raw_input("What is your guess[1-10]: "))
    if number > r:
        print "sorry you guessed to high"
    elif number < r:
        print "You guessed to low"
    else:
        print "You guessed right thanks for playing"
        break

您可以更改while循环以涵盖条件：

import random
print "Welcome to the number guessing game"
print "I have my number..."
number = 0
r = random.randint(1, 10)
while number != r:
    number = int(raw_input("What is your guess[1-10]: "))
    if number > r:
        print "sorry you guessed to high"
    elif number < r:
        print "You guessed to low"
print "You guessed right thanks for playing"

我想在python上做基本的猜数游戏

1 个答案: