我试图将两个查询的结果回显到表中。它似乎将结果拆分为单独的行而不是彼此相邻。 spaceid和venueid的值在db中匹配。
这是我的代码:
<?php
$con=mysqli_connect("host","username","pword","mydb");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT venue.venuename FROM venue INNER JOIN space ON space.spaceID=venue.venueID;";
$sql .= "SELECT space.room, space.costoftables FROM space INNER JOIN venue ON space.spaceID=venue.venueID;";
?>
<table class="tablesorter" width="600px" border="1" cellpadding="1" cellspacing="1" id="myTable">
<thead>
<tr>
<th>Venue Name</th> <th>Room</th> <th>Cost</th>
</tr></thead><tbody>
<?php
// Execute multi query
if (mysqli_multi_query($con,$sql)){
do{
// Store first result set
if ($result=mysqli_store_result($con)) {
// Fetch one and one row
while ($row=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>".$row['venuename']."</td>";
echo "<td>".$row['room']."</td>";
echo "<td>".$row['costoftables']."</td>";
}
?>
</tr>
<?php
}
}
while (mysqli_next_result($con));
}
mysqli_close($con);
?>
</tbody>
</table>
结果如下: Results